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puteri [66]
3 years ago
10

i really need help with my math assignment it’s normal distributions and i need this to graduate tomorrow if anyone can help it

would be deeply appreciated
Mathematics
1 answer:
Vika [28.1K]3 years ago
7 0
Where’s the work you need help with :)
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In circle J with mZHIK = 54 and HJ = 13 units find area of sector
omeli [17]
The answer would be 79.64
I circled the formula for the area of a sector.

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3 years ago
Someone please help I’m lost
luda_lava [24]
It’s because it’s intersecting so WXY and ZYX are congruent
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2 years ago
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Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

5 0
3 years ago
Match the English word or phrase to its math equivalent.
nydimaria [60]
Sum is addition, less than is subtraction, equals is is, division is of and multiplication is per
5 0
3 years ago
In the 2009-2010 school year in country A, there were 92,000 foreign students from country B. This number I 23% more than the nu
max2010maxim [7]

Answer:

\approx74796

Step-by-step explanation:

GIVEN: In the 2009-10 school year in country A, there were 92,000 foreign students from country B. This number is 23\% more than the number of students from country C.

TO FIND: How many foreign students were from country C.

SOLUTION:

Total foreign students from country B =92000

let the foreign students from country C be x

As the students from country B is 23\% more than the country C

Students from country B

92000=\frac{123}{100}x

x=\frac{9200000}{123}

x\approx74796

Hence the number of students from country C are 74796

8 0
3 years ago
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