An easy way to do this is by using the simplest equations you can:
x + y and x - y
(3, 5) is (x, y). all you have to do is plug those into your equations and get a result, so:
x + y = 8
(because 3 + 5 = 8)
x - y = -2
(because 3 - 5 = -2)
and those can serve as your system of equations.
you can check it by solving by substitution:
x - y = -2
x + y = 8
solve one of the equations for a single variable:
x = y - 2
plug it into the second equation:
(y - 2) + y = 8
y - 2 + y = 8
2y - 2 = 8
2y = 10
y = 5
then plug that result back into the equation:
x + y = 8
x + 5 = 8
x = 3
Those quantities can't be compared. "Kg" is a unit of mass,
whereas "lb" is a unit of weight. You can't convert mass to
weight without knowing the acceleration of gravity in the place
where the mass is.
For example:
-- 75 kg of mass weighs 418 lb on Jupiter.
-- 75 kg of mass weighs 62.6 lb on Mars
-- 75 kg of mass weighs 27.4 lb on the Moon.
-- 75 kg of mass weighs 165.3 lb on Earth.
-- 75 kg of mass weighs 11.1 lb on Pluto.
It all depends where you take your 75 kg.
Answer:
C, 108
Step-by-step explanation:
rectangles
8x3 = 24
8x4 = 32
8x5 = 40
triangles
3x4 = 12
you dont really have to divide by 2 since theres two triangles
24+32+40+12 = 108
hi!
o would have to be 6
p would be 10
adn so the distance would be 12
the ratio would really be 8:4 and then would simplify to 2:1
That's why o would hae to be 6 because NO is 8 and OP is 4
Hope this helps!
Answer:
t = 2
Step-by-step explanation:
Notice that this expression for the projectile's path is that of a quadratic function with negative leading term. The graph of it therefore consists of a parabola with the branches pointing down (due to he negative leading coefficient). Therefore, the maximum of such parabola will reside at its vertex.
Recall that the formula for the position of the vertex in a general parabolic function of the form: 
, is given by the expression: 
In our case, the variable "x" is in fact "t", the leading coefficient (
) is -5, and the coefficient for the linear term (
) is 20.
Therefore, the maximum of the path will be when 
