If a system of linear equations has no solution, what do you know about the slopes and y-intercepts of the graphs of the equatio
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Answer:
<em>Answer: Quadrant 4</em>
Step-by-step explanation:
<u>Graph of Functions </u>
Let's analyze the function
To better understand the following analysis, we'll factor y
For y to have points in the first quadrant, at least one positive value of x must produce one positive value of y. It's evident that any x greater than 0 will do. For example, x=1 will make y to be positive in the numerator and in the denominator, so it's positive
For y to have points in the second quadrant, at least one negative value of x must produce one positive value of y. We need two of the factors that are negative. It can be seen that x=-2 will make y as positive, going through the second quadrant.
For the third quadrant, we have to find at least one value of x who produces a negative value of y. We only need to pick a value of x that makes one or all the factors be negative. For example, x=-4 produces a negative value of y, so it goes through the third quadrant
Finally, the fourth quadrant is never reached by any branch because no positive value of x can produce a negative value of y.
Answer: Quadrant 4