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3 years ago

Which of the following substances would have the highest dispersion forces? Why?

Chemistry

1 answer:

Alenkinab [10]3 years ago

8 0

Answer:

Explanation:

Dispersion force or London force is the force of attraction between two atoms or molecules in a substance in solid , liquid and gas . In gas , this force is minimum and in solid this force is maximum . In solid this force is maximum in metals in which this force forms metallic bond .

Among the given substances , Si , Sn , MgO , C₂₀H₄₂ are solid , so dispersion force will be high in them .

Among all as mentioned above , Si will have highest dispersion force . It is due to four covalent bond that bind two atoms of Si in solid silicon . Its three dimensional crystal structure consist of silicon atoms , all bound by four covalent bonds .

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What is the molecular weight, density, and how many moles in

OverLord2011 [107]

Answer:

1) Molecular weight: 18g/mol

Density: at room temperature (25ºC) is 0.997g/mL

Moles: 0.55moles

2) Molecular weight: 182g/mol

Density: at room temperature (25ºC) is 1.11g/mL

Moles: $2.2x10^{-4}moles$

Explanation:

1) The molecular formula of water is $H_{2}O$ thus, the molecular weight is the sum of the weights of its atoms.

H: 1g/mol x 2 = 2g/mol

O: 16g/mol x 1 = 16g/mol

$H_{2}O$ : 2g/mol + 16g/mol = 18g/mol

The density (δ) of water at room temperature (25ºC) is 0.997g/mL

Therefore, the weight (m) of 1mL of water is:

m = δ.V = $0.997\frac{g}{mL}. 1mL = 0.997g$

Multiplying the mass by its molecular weight gives the number of moles:

$\frac{0.997g }{18g/mol} = 0.55 moles$

2) The molecular formula of benzophenone is $C_{13}H_{10}O$ thus, the molecular weight is the sum of the weights of its atoms.

C: 12g/mol x 13 = 156g/mol

H: 1g/mol x 10 = 10g/mol

O: 16g/mol x 1 = 16g/mol

$C_{13}H_{10}O$ : 156g/mol + 10g/mol + 16g/mol = 182g/mol

The density (δ) of water at room temperature (25ºC) is 1.11g/mL

Multiplying the mass by its molecular weight gives the number of moles:

$\frac{0.04g }{182g/mol} = 2.2x10^{-4}moles$

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ANEK [815]

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