The electron configuration that belongs to the atom with the lowest first ionization energy is francium.
<h3>What is ionization energy? </h3>
Ionization energy is defined as the minimum amount of energy required to remove the most loosely electron present in outermost shell.
<h3>Ionization energy across period</h3>
Ionization energy increase as we move from left to right in the period. This can be explained as when we move from left to right along period new electron is added to the same shell which increase the nuclear charge. Hence results int he decrease in size. Due to this decrease in size more energy is required to remove electron from outermost shell.
<h3>Ionization energy along group</h3>
Ionization energy decrease as we move from top to bottom along group. This can be explained as we move from top to bottom new electron is added to new shell. Due to addition of new shell the size of atom increases which results in the decrease in the nuclear charge. Due to this less amount of energy is needed to remove an electron.
Thus, we concluded that the electron configuration that belongs to the atom with the lowest first ionization energy is francium.
learn more about ionization energy:
brainly.com/question/1602374
#SPJ4
The answer is A; it shows that the number of rabbits increase as the times increases
I think the answer most be d
Answer:
P = 20atm
Explanation:
P1 = 10atm
T1 = 10K
P2 = ?
T2 = 20K
This question requires the use of pressure law which states that the pressure of a fixed mass of gas is directly proportional to its temperature provided its volume remains constant
Mathematically,
P = kT, k = P / T
P1 / T1 = P2 / T2 = P3 / T3=........=Pn / Tn
P1 / T1 = P2 / T2
P2 = (P1 × T2) / T1
P2 = (10 × 20) / 10
P2 = 20atm
The final pressure of the gas is 20atm
Answer:

Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to find the molecular formula of the given compound by firstly calculating both moles and grams of carbon in carbon dioxide and hydrogen in water, as the only sources of these elements derived from the compound x due to its combustion:


Now, since the addition of carbon and hydrogen is about 6.50 grams, we infer the compound has no oxygen, that is why we now set the mole ratios in the empirical formula for both C and H as shown below:

Yet it cannot be decimal, that is why we multiply by 4 to get the correct whole-numbered empirical formula:

Whose molar mass is 64.09 g/mol, which makes the ratio of molar masses:

Therefore, the molecular formula is twice the empirical one:

Regards!