The #4,832,504 in word from
2 answers:
You might be interested in
Answer:
Step-by-step explanation:
a) The game tree for k = 5 has been drawn in the uploaded picture below where C stands for continuing and S stands for stopping:
b) Say we were to use backward induction we can clearly observe that stopping is optimal decision for each player in every round. Starting from last round, if player 1 stops he gets $3 otherwise zero if continues. Hence strategy S is optimal there.
Given this, player 2’s payoff to C is $3, while stopping yields $4, so second player will also chooses to stop. To which, player 1’s payoff in k = 3 from C is $1 and her payoff from S is $2, so she stops.
Given that, player 2 would stop in k = 2, which means that player 1 would stop also in k = 1.
The sub game perfect equilibrium is therefore the profile of strategies where both players always stop: (S, S, S) for player 1, and (S, S) for player 2.
c) Irrespective of whether both players would be better off if they could play the game for several rounds, neither can credibly commit to not stopping when given a chance, and so they both end up with small payoffs.
i hope this helps, cheers
Answer:
The given expression on multiplying is
Step-by-step explanation:
Consider the given two expressions and
We have multiply both expressions,
To multiply two terms first multiply constant numbers that is 6 × 2 = 12
For x , y and z apply property of exponent,
Then power of x together will be,
Similarly for y powers,
Since first term do not have any expression for z so it will remain same.
Thus, the given expression on multiplying become,
is