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8090 [49]
2 years ago
6

Graph the image of square CDEF after a reflection across the x-axis​

Mathematics
1 answer:
Rina8888 [55]2 years ago
5 0

Answer:

If you have a general point (x, y), and you reflect it across the x-axis, the coordinates of the new point will be:

(x,-y)

So we only change the sign of the y-component.

Now, if we do a reflection across the x-axis of a whole figure, then we apply the reflection to all the points that make the figure.

Then, we could just apply the reflection to the vertices of the square, then graph the new vertices, and then connect them, that is equivalent to graph the image of the square after the reflection.

The original vertices are:

C = (-3, 7)

D = (0, 7)

E = (0, 10)

F = (-3, 10)

Now we apply the reflection, remember that this only changes the sign of the y-component, then the new vertices are:

C' = (-3, -7)

D' = (0, -7)

E' = (0, - 10)

F' = (0, - 10)

Now we need to graph these points and connect them to get the reflected figure, the image can be seen below.

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7) Find EC<br> 16<br> E-<br> B<br> D<br> С<br> 49<br> 30
lana66690 [7]
Answer:

EC = 35

Step-by-step explanation:

The whole entire line measures 49

DB measures 30

49 - 30 = 19 or ED

But we’re looking for EC so…

19 + 16 = 35

EC = 35
3 0
3 years ago
23.0833333333 in fraction form
Black_prince [1.1K]

Answer:

230833333333/10000000000

Step-by-step explanation:

Well to write this as a fraction you will first write 23.0833333333 as our numerator

Now you would multiply numerator by denominator which you could put 1 as denominator and multiply by 10 and you get your whole number/your answer.

Hope this helps have a great day:)

4 0
2 years ago
Figure 1 is similar to figure 2
Fudgin [204]
Yes I think that is correct
5 0
3 years ago
Read 2 more answers
Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. We learned about the de
attashe74 [19]

The question is incomplete. Here is the complete question.

Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.

a) Determine the arc length to the nearest tenth of an inch.

b) Explain why the following proportion would solve for the length of AC below: \frac{x}{12\pi } = \frac{130}{360}

c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.

Note: The image in the attachment shows the arc to solve this question.

Answer: a) 9.4 in

c) x = 13.6 in

Step-by-step explanation:

a) \frac{arclength}{2\pi.r } = \frac{mAB}{360}, where:

r is the radius of the circumference

mAB is the angle of the arc

arc length = \frac{mAB.2.\pi.r }{360}

arc length = \frac{90.2.3.14.6}{360}

arc length = 9.4

The arc lenght for the image is 9.4 inches.

b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):

\frac{x}{2.6.\pi } = \frac{130}{360}

\frac{x}{12\pi } = \frac{130}{360}

c) Resolving (b):

x = \frac{130.12.3.14}{360}

x = 13.6

The arc length for the image is 13.6 inches.

6 0
3 years ago
A salesman earns a Commission of $630 for selling $3050 in merchandise
agasfer [191]

Answer:

ok so lets find what percentage 630 is of 3050

630/3050=0.20655737704

so about 20.7%

Hope This Helps!!!

7 0
2 years ago
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