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8090 [49]
2 years ago
6

Graph the image of square CDEF after a reflection across the x-axis​

Mathematics
1 answer:
Rina8888 [55]2 years ago
5 0

Answer:

If you have a general point (x, y), and you reflect it across the x-axis, the coordinates of the new point will be:

(x,-y)

So we only change the sign of the y-component.

Now, if we do a reflection across the x-axis of a whole figure, then we apply the reflection to all the points that make the figure.

Then, we could just apply the reflection to the vertices of the square, then graph the new vertices, and then connect them, that is equivalent to graph the image of the square after the reflection.

The original vertices are:

C = (-3, 7)

D = (0, 7)

E = (0, 10)

F = (-3, 10)

Now we apply the reflection, remember that this only changes the sign of the y-component, then the new vertices are:

C' = (-3, -7)

D' = (0, -7)

E' = (0, - 10)

F' = (0, - 10)

Now we need to graph these points and connect them to get the reflected figure, the image can be seen below.

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T is between S and U ST = X-6, SU = 10 units, and TU = 2x - 8. Find the length of ST.
abruzzese [7]

Answer:

<h2>B.  ST = 2</h2><h2 />

Step-by-step explanation:

|<--------------  10 --------------------->|

S-------------------T--------------------U

            X-6              2X - 8

FIND: ST

SOLUTION:

ST + TU = SU

x - 6 + 2x - 8 = 10

combine like terms:

3x - x = 10 + 8 + 6

x = 24/3

x = 8

plugin the value of x= 8 into the ST = x - 6

ST = x - 6

ST = 8 - 6

ST = 2

proof:

x - 6 + 2x - 8 = 10

8 - 6 + 2(8) - 8 = 10

10 = 10 ---OK

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Answer:

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Step-by-step explanation:

I'm sorry if I'm wrong

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