(fg)(x)=f(g(x))=4(g(x))²-5=4(x+3)²-5=4x²+24x+31
The number of miles in a day at which the rental costs for Company A and Company B are the same is 140 miles
<h3>Rental cost</h3>
Let
Company A:
90 + 0.20x
Company B:
20 + 0.70x
90 + 0.20x = 20 + 0.70x
90 - 20 = 0.70x - 0.20x
70 = 0.50x
- Divide both sides by 0.50
x = 70/0.50
x = 140 miles
Therefore, the number of miles in a day at which the rental costs for Company A and Company B are the same is 140 miles
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Answer:
D. 9990 possible combinations
Step-by-step explanation:
The first digit has 10 choices (can be all of them), the second digit also has 10 choices. The third and fourth digits also have 10 choices.
Multiply them together you get 10*10*10*10 = 10000 possible combinations.
But since all 4 characters cannot be the same, we subtract 10 from 10000 (there are 10 combinations which the 4 characters are the same: 1111, 2222, 3333, 4444, 5555, 6666, 7777, 8888, 9999, and 0000) and we get 9990.
