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2 years ago

A deep freezer has a temperature of -6°C when it is turned off.

Mathematics

1 answer:

Xelga [282]2 years ago

4 0

Answer:

y = -6 + 1.2*x is the answer I would use, but see the note below.

Step-by-step explanation:

Let x = the number of minutes.

Let y = the temperature at any given time.

y = -6 + 1.2*x

This is the equation that you would use if you were calculating y with a calculator. If you are in a chemistry class it should be written as

y = - 6°C + 1.2°x/ min

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What do you know to be true about the values of a and b?

gizmo_the_mogwai [7]

Answer:

Can't be determined

Step-by-step explanation:

You just don't have enough info!

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3 years ago

Find the root of 11+2square30

EleoNora [17]

$\\ \sf\longmapsto \sqrt{11+2^230}$

$\\ \sf\longmapsto \sqrt{11+4(30)}$

$\\ \sf\longmapsto \sqrt{11+120}$

$\\ \sf\longmapsto \sqrt{131}$

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2 years ago

SOMEONE PLEASE HELP ME ASAP PLEASE!!! (the answer is not 16)

dem82 [27]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Round to the nearest tenth: 6.932635 6.9 6 6.8 7

Lera25 [3.4K]

6.932635
^ This is the tenths place.

Since the number after it is less than 5, we round down.

So we round to:

6.9

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3 years ago

Read 2 more answers

A $20,000 business computer depreciates at a rate of 15% per year. What equation would model the value of the computer?

tekilochka [14]

Answer:

$A = 20,000(0.85)^t$

Step-by-step explanation:

We will use the formula for compound interest here

where $A = p( 1 + r)^t$

A=future value for any sum

P=present value of the sum

r= yearly interest rate, it should be expressed in decimal

t=time period , it should be in years

______________________________

given in the problem

p = $20,000

r = 15% (in decimal 15/100 = 0.15)

t is the time for which equation is to be model to find future value p

since, rate is for depreciation we need to take negative value of rate as value for computer will decrease

thus

r = -0.15

using the above values in formula $A = p( 1 + r)^t$

$A = p( 1 + r)^t\\A = 20,000(1 - 0.15)^t\\A = 20,000(0.85)^t$

Thus, model equation for the value of the computer is $A = 20,000(0.85)^t$

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3 years ago