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shtirl [24]
2 years ago
15

Which is the product of 79 and 6?

Mathematics
2 answers:
Pepsi [2]2 years ago
8 0

Answer:

the answer is 474

.......

____ [38]2 years ago
3 0
The product of 79 and 6 is 474
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F(x) and g(x) are a differentiable function for all reals and h(x) = g[f(5x)]. The table below gives selected values for f(x), g
astraxan [27]
By the chain rule,

h(x)=g(f(5x))\implies h'(x)=5g'(f(5x))f'(5x)

so

h'(1)=5g'(f(5))f'(5)

It's kinda hard to tell which values are which in the table, but if I had to guess, you should get

h'(t)=5g'(f(5))f'(5)=5g'(2)(0)=0
5 0
3 years ago
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How do I find the reciprocal of the fractions 2/3 and 8/3
Mice21 [21]

2/3 reciprocal is 3/2, & 8/3 reciprocal is 3/8. The numbers are just filled to find their reciprocal!

5 0
3 years ago
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Help me with this please
insens350 [35]
%69 of visited only one place
4 0
3 years ago
PLZ HELP E!!!!!!! WILL MARK BRAINLIEST
vitfil [10]

Answer:

1

+

sec

2

(

x

)

sin

2

(

x

)

=

sec

2

(

x

)

Start on the left side.

1

+

sec

2

(

x

)

sin

2

(

x

)

Convert to sines and cosines.

Tap for more steps...

1

+

1

cos

2

(

x

)

sin

2

(

x

)

Write  

sin

2

(

x

)

as a fraction with denominator  

1

.

1

+

1

cos

2

(

x

)

⋅

sin

2

(

x

)

1

Combine.

1

+

1

sin

2

(

x

)

cos

2

(

x

)

⋅

1

Multiply  

sin

(

x

)

2

by  

1

.

1

+

sin

2

(

x

)

cos

2

(

x

)

⋅

1

Multiply  

cos

(

x

)

2

by  

1

.

1

+

sin

2

(

x

)

cos

2

(

x

)

Apply Pythagorean identity in reverse.

1

+

1

−

cos

2

(

x

)

cos

2

(

x

)

Simplify.

Tap for more steps...

1

cos

2

(

x

)

Now consider the right side of the equation.

sec

2

(

x

)

Convert to sines and cosines.

Tap for more steps...

1

2

cos

2

(

x

)

One to any power is one.

1

cos

2

(

x

)

Because the two sides have been shown to be equivalent, the equation is an identity.

1

+

sec

2

(

x

)

sin

2

(

x

)

=

sec

2

(

x

)

is an identity

Step-by-step explanation:

7 0
2 years ago
(5+6b^3)^2 expand and combine like terms
Drupady [299]

Answer:

( 5 + 6b^3)^2 = 36b^6 + 60b^3 + 25

Step-by-step explanation:

(a + b)^2 = a^2 + b^2 + 2ab

So,

        (5 + 6b^3)^2 = (5)^2 + (6b^3)^2 + 2 (5)(6b^3)

                       = 25 + 36b^6 + 60b^3

7 0
3 years ago
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