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Anika [276]
4 years ago
13

The rectangle has an area of 4(x+3) square units.

Mathematics
1 answer:
Serggg [28]4 years ago
5 0
Suppose there is a rectangle with a width and length of x and y. The area would be xy.

A rectangle with width and length 2x and 2y would have an area of 4xy.

In essence, when you multiply the lengths by 2, the area multiplies by 2 SQUARED.

4(4(x+3)) = 16(x+3).

The ratio will be the same for any value of x because the area is still being multiplied by the same 2².
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16x²-102X=-36<br> How to write this in Vertex form
boyakko [2]

Answer:

x

Step-by-step explanation:

5 0
3 years ago
∆ABC is an isosceles triangle in which angles B and C are congruent.
Brut [27]
Since B and C are congruent, that means that 4x+10=x+34. Using the addition property of equality, I challenge you to solve for x! After you do that, you can note that all the angles in a triangle add up to 180, so 4x+10+x+34+angleA=180. When you find x, you can substitute that in.

If you need help with the addition property of equality for variables, here's an example - 5x+23=4x+3. Subtracting 3 from both sides, we get 5x+20=4x. Next, we can subtract 5x from both sides to get -x=20 and divide both sides by -1 to get x=-20.

Good luck, and feel free to ask with any questions!
4 0
3 years ago
Read 2 more answers
robert has a piece of rope 12 1/2 feet long. he cut rope into pieces that are 1 1/4 feet long. How many of the shorter pieces wi
Gemiola [76]

Answer:

divide 25.5 by 6

or change them to fractions

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Step-by-step explanation:

5 0
3 years ago
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The length of a rectangle is five times its width. if the perimeter of the rectangle is 96 m , find its length and width.
givi [52]
<span>The length of a rectangle is five times its width, and if the perimeter of the rectangle is 96 m then the length would be 19 m.</span>
8 0
4 years ago
Find the two small as possible solutions ​
solong [7]

Answer:  \bold{b)\quad \dfrac{5}{6},\ \dfrac{25}{6}}

<u>Step-by-step explanation:</u>

12cos\bigg(\dfrac{2\pi}{5}x\bigg)+10=16\\\\\\12cos\bigg(\dfrac{2\pi}{5}x\bigg)=6\\\\\\cos\bigg(\dfrac{2\pi}{5}x\bigg)=\dfrac{1}{2}\\\\\\cos^{-1}\bigg[cos\bigg(\dfrac{2\pi}{5}x\bigg)\bigg]=cos^{-1}\bigg(\dfrac{1}{2}\bigg)

\text{Use the Unit Circle to determine when}\ cos=\dfrac{1}{2}\quad \rightarrow \quad\text{at}\ \dfrac{\pi}{3}\ and \ \dfrac{5\pi}{3}\\\\\\\dfrac{2\pi}{5}x=\dfrac{\pi}{3}\qquad and\qquad \dfrac{2\pi}{5}x=\dfrac{5\pi}{3}\\\\\\\bigg(\dfrac{5}{2\pi}\bigg)\dfrac{2\pi}{5}x=\dfrac{\pi}{3}\bigg(\dfrac{5}{2\pi}\bigg)\quad and\quad \bigg(\dfrac{5}{2\pi}\bigg)\dfrac{2\pi}{5}x=\dfrac{5\pi}{3}\bigg(\dfrac{5}{2\pi}\bigg)\\\\\\.\qquad \qquad \large\boxed{x=\dfrac{5}{6}\qquad and \qquad x=\dfrac{25}{6}}

6 0
3 years ago
Read 2 more answers
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