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solong [7]
3 years ago
7

Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skat

eboards and a standard deviation of 55 skateboards.
(a) On what percent of the days last year did the factory produce 20,555 skateboards or fewer?
(b) On what percent of the days last year did the factory produce 20,610 skateboards or more?
(c) On what percent of the days last year did the factory produce 20,445 skateboards or fewer?
Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

Answer:

This can be solved by using the empirical rule for a normal distribution.

Step-by-step explanation:

A. The number of skateboards given is one standard deviation above the mean. Approximately 68% of the data points lie within the range plus and minus one standard deviation of the mean. Therefore the required percentage is:

68 + 16 = 84%.

B. The given number of skateboards is two standard deviations above the mean. Approximately 95% of the data points lie within the range plus and minus two standard deviations of the mean. Therefore the required percentage is:

5/2 = 2.5%

C.The given number of skateboards is one standard deviations below the mean. Therefore the required percentage is:

16%.

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Answer:

1/2

Step-by-step explanation:

So you have 12 bags total.

2 are 1/6 so their total weight is 1/3

2 are 1/3 so their total weight is 2/3

3 are 1/2 so their total weight is 3/2

4 are 2/3 so their total weight is 8/3

1 is 5/6 so their total weight is 5/6

Now add all of these up:

1/3 + 2/3 + 3/2 + 8/3 + 5/6 = 36/6 = 6

Then divide by the number of bags to get the average weight: 6/12 = 1/2

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3 years ago
I don't understand how to go about solving this equation more specifically the "y". Any help is appreciated. (:
Archy [21]

Answer:

y^2/x^6

apply exponent rule:

x^-2/x^4=1/x^4-(-2)=y/y^-1 x^4 -(-2)

then you subtract 4-(-2)=6

y/x^6 y^-1

cancel out the common factor: y^-1 and you get

y^2

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42

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A car's velocity is modeled by
Igoryamba

In accordance with the function <em>velocity</em>, the car will have a complete stop after 6 seconds.

<h3>When does the car stop?</h3>

Herein we have a function of the velocity of a car (v), in feet per second, in terms of time (t), in seconds. The car stops for t > 0 and v = 0, then we have the following expression:

0.5 · t² - 10.5 · t + 45 = 0

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To learn more on quadratic equations: brainly.com/question/2263981

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