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r-ruslan [8.4K]
3 years ago
5

I'm single as a pringle and ready to mingle

Mathematics
2 answers:
Nitella [24]3 years ago
5 0

nice same here but im NOT mingling with you

oksano4ka [1.4K]3 years ago
3 0

Answer:

mmmmmm points

Step-by-step explanation:

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17-(4k-2) larger than or equal to 2 (k+3)
Schach [20]
17 - (4k - 2) ≥ 2 (k + 3)

17 - 4k + 2 ≥ 2k + 6

-4k + 19 ≥ 2k + 6

19 - 6 ≥ 2k + 4k

13 ≥ 6k

13/6 ≥ k

Done!
3 0
4 years ago
Hello, help me please)
AlladinOne [14]

Answer:

Given equation:

10^{5x-2}=2^{8x-3}

Take natural logs of both sides:

\implies \ln 10^{5x-2}= \ln 2^{8x-3}

\textsf{Apply log Power law}: \quad \ln_ax^n=n\ln_ax

\implies (5x-2)\ln 10=(8x-3) \ln 2

Expand brackets:

\implies 5x\ln 10 - 2\ln 10=8x \ln 2 -3 \ln 2

Collect like terms:

\implies 5x\ln 10 - 8x \ln 2 =2\ln 10-3 \ln 2

Factor left sides:

\implies x(5\ln 10 - 8 \ln 2) =2\ln 10-3 \ln 2

\textsf{Apply log Power law}: \quad \ln_ax^n=n\ln_ax

\implies x(\ln 10^5 - \ln 2^8) =\ln 10^2- \ln 2^3

\textsf{Apply log Quotient law}: \quad \ln_a\frac{x}{y}=\ln_ax - \ln_ay

\implies x\left(\ln\left(\dfrac{10^5}{2^8}\right)\right) =\ln\left(\dfrac{10^2}{2^3}\right)

Simplify:

\implies x\left(\ln\left(\dfrac{3125}{8}\right)\right) =\ln\left(\dfrac{25}{2}\right)

\implies x=\dfrac{\ln\left(\dfrac{25}{2}\right)}{\ln\left(\dfrac{3125}{8}\right)}

\implies x=0.4232297737...

6 0
2 years ago
5.(03.06)
maw [93]

Answer:

y = 3 \div 4x + 10

6 0
3 years ago
WILL GIVE BRIANLIEST!!!!!!!!!!!!!!!!!!!!! picture down below ↓↓↓↓↓↓
NARA [144]

Answer:

C

Step-by-step explanation:

A and c are parallel

B and d are parallel

A and c are intersecting

7 0
3 years ago
10,996 rounded to the neart thousand
Sholpan [36]
<h3>Rounding it to the nearest thousand:</h3>

11,000

<h2>Answer:</h2>

11,000

3 0
4 years ago
Read 2 more answers
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