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r-ruslan [8.4K]
3 years ago
5

I'm single as a pringle and ready to mingle

Mathematics
2 answers:
Nitella [24]3 years ago
5 0

nice same here but im NOT mingling with you

oksano4ka [1.4K]3 years ago
3 0

Answer:

mmmmmm points

Step-by-step explanation:

You might be interested in
What is the first geometric sequence below
ale4655 [162]
Notice that if you go forward, the common ratio is 5.  Each new term is found by mult. the previous term by 5.

If, on the other hand, you go backwards (terms decreasing), then you divide a term to find what the previous term was.

Here, divide 1 by 5 to find the first term.  It's 1/5.
5 0
3 years ago
Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the
dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

I = \int \int_E \int zdV where E is bounded by the cylinder y^2 + z^2 = 81 and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and y^2 + z^2 = 81

∴ z^2 = 81 - y^2

z = \sqrt{81 - y^2}

Thus, z lies between 0 to \sqrt{81 - y^2}

GIven curve x = 0 and y = 9x

x =\dfrac{y}{9}

As such,x lies between 0 to \dfrac{y}{9}

Given curve x = 0 , x =\dfrac{y}{9} and z = 0, y^2 + z^2 = 81

y = 0 and

y^2 = 81 \\ \\ y = \sqrt{81}  \\ \\  y = 9

∴ y lies between 0 and 9

Then I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix}    ^ {\sqrt {{81-y^2}}}_{0} \ dxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix}  \dfrac{(\sqrt{81 -y^2})^2 }{2}-0  \end {bmatrix}     \ dxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix}  \dfrac{{81 -y^2} }{2} \end {bmatrix}     \ dxdy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0}    \ dy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix}     \ dy

I = \int^9_{y=0}  \begin {bmatrix}  \dfrac{{81 \  y -y^3} }{18} \end {bmatrix}     \ dy

I = \dfrac{1}{18} \int^9_{y=0}  \begin {bmatrix}  {81 \  y -y^3}  \end {bmatrix}     \ dy

I = \dfrac{1}{18}  \begin {bmatrix}  {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}}  \end {bmatrix}^9_0

I = \dfrac{1}{18}  \begin {bmatrix}  {40.5 \ (9^2) - \dfrac{9^4}{4}}  \end {bmatrix}

I = \dfrac{1}{18}  \begin {bmatrix}  3280.5 - 1640.25  \end {bmatrix}

I = \dfrac{1}{18}  \begin {bmatrix}  1640.25  \end {bmatrix}

I = 91.125

4 0
3 years ago
Yellow rectangles= X Yellow squares = positive Red squares = negative
Viefleur [7K]

Answer:

that is a great question, could u explain more? im serious

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
15 points pls brainliest show your work no calculator
FinnZ [79.3K]

Based on the calculations on the given expressions, the correct answers are as follows:

  1. Expression = 25/2 or 12.5.
  2. Difference = 5.
  3. n = 6.
  4. Expression = 31/15.
  5. Prime factorization of 96 = 2⁵ × 3¹.
  6. Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, and 48.
  7. Inequality = 2³ < 3².
  8. Total amount = $255.
  9. Expression = 5.

<h3>How to evaluate this expression?</h3>

In order to evaluate this expression, we would substitute the value of x into upper and lower part respectively and then simplify as follows:

Expression = (6x + 8)/(4x - 24)

Expression = (6(7) + 8)/(4(7) - 24)

Expression = (42 + 8)/(28 - 24)

Expression = 50/4

Expression = 25/2 or 12.5.

Next, we would translate the given word problem into an algebraic expression:

Difference = 10 - 5

Difference = 5.

To solve for the value of n in the given expression:

-15 + n = -9

n = -9 + 15

n = 15 - 9

n = 6.

Expression = 2/3 + 1 2/5

Expression = 2/3 + 7/5

Expression = (10 + 21)/15

Expression = 31/15.

Next, we would write the prime factorization of 96:

Factors of 96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, and 96.

96 = 2 × 2 × 2 × 2 × 2 × 3

96 = 2⁵ × 3¹.

Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, and 48.

<h3>How to determine the inequality symbol?</h3>

2³ __  3²  ≡  8 __ 9

Since 8 is less than 9, the inequality symbol which would complete the number sentence is < and it would be written as follows:

Inequality = 2³ < 3².

Next, we would calculate the total amount of money that KeeKee will spend:

Initial cost = 3 × $60 = $180

Total amount = initial cost + final cost

Total amount = $180 + $75

Total amount = $255.

Finally, we would simplify the given expression:

Expression = 3² + 2(12 ÷ 4 - 2 + 3)

Applying BODMAS, we have:

Expression = 3² + 2(3 - 2 + 3)

Expression = 3² + 2(3 - 5)

Expression = 3² + 2(-2)

Expression = 9 - 4

Expression = 5.

<h3>What is an expression?</h3>

An expression can be defined as a mathematical equation which is used to show the relationship existing between two or more variables and numerical quantities.

Read more on expressions here: brainly.com/question/28260012

#SPJ1

7 0
2 years ago
Writethecoordinatesoftheverticesafteradilationwithascalefactorof 1 5 ,centeredattheorigin. y x -10 10 -10 10 0 S T U S(5, -10) →
densk [106]

Answer:

The answer is below

Step-by-step explanation:

Write the coordinates of the vertices after a dilation with a scale factor of 1/5 , centered at the origin.

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.

Dilation is the reduction or enlargement in the size of an object by a scale factor (k). If k > 1, it is an enlargement and if k < 1, it is a reduction. If a point A(x, y) is dilated by a factor k, the new point is A'(kx, ky).

Therefore, if the vertices are dilated with a scale factor of 1/5 , centered at the origin. The new point is:

S(5, -10) → S′(1 , -2) T(10, -10) → T′(2 , -2) U(5, 10) → U′(1 , 2)

6 0
3 years ago
Read 2 more answers
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