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3 years ago

13

Work out the volume of the cuboid in m

1 answer:

Marina CMI [18]3 years ago

6 0

Answer: V= 4500m^3

Explanation:
V= length x width x height
V = 600 x 3 x 2.5
V = 600 x 7.5
V = 4500

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matrenka [14]

X will be less than 18 or X<18

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4 years ago

Can u help with 8 and 10? And check the rest??

Hoochie [10]

7.) 4x greater because 8*8=64 and 4*4=16 64/16=4
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9.) 32 because the square root of 64 is 8 so each side is 8 square feet
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3 0

3 years ago

Read 2 more answers

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago

Please help me out with this!!

galina1969 [7]

Answer:

see explanation

Step-by-step explanation:

Given

x + $\frac{1}{2}$ ≤ - 3 or x - 3 > - 2

Solve the left and right inequalities separately, that is

x + $\frac{1}{2}$ ≤ - 3 ( isolate x by subtracting $\frac{1}{2}$ from both sides )

x ≤ - 3 - $\frac{1}{2}$ , that is

x ≤ - $\frac{6}{2}$ - $\frac{1}{2}$ , thus

x ≤ - $\frac{7}{2}$

OR

x - 3 > - 2 ( isolate x by adding 3 to both sides )

x > 1

Solution is

x ≤ - $\frac{7}{2}$ or x > 1

7 0

3 years ago

A line of best fit was drawn for 5 data points. what is the maximum number of these data points that may not actually be on the

jenyasd209 [6]

[b.3] ^_^
hopefully i helped (0-0)

4 0

3 years ago

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