3 years ago

Help me please

Mathematics

1 answer:

vlabodo [156]3 years ago

3 0

Answer:

Step-by-step explanation:

X=8.50

y=9.50

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Solve for the equation for the interval [0, 2pi). sec x/2 = cos x/2

Alenkinab [10]

Sec(x/2) = 1/cos(x/2)

sec(x/2)=cos(x/2) ----> cos^2(x/2)=1 ---> cos(x/2) = -1 and cos(x/2) = 1

Cos(x/2)=1 --- > x/2 = 0, only. x = 0;

cos(x/2)=-1 ----> x/2 = pi -> x = 2pi. But the statement says [0,2pi), so 2pi can not be chosen.

Only x = 0.

In fact, your equation is equivalent to sec(x)=cos(x), for x in [ 0, pi), so yes, only x = 0 .

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omeli [17]

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3 years ago

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Does anybody want to help me with a math question?

Genrish500 [490]

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