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3 years ago

Help me please

Mathematics

1 answer:

vlabodo [156]3 years ago

3 0

Answer:

Step-by-step explanation:

X=8.50

y=9.50

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To determine whether or not they have a certain desease, 100 people are to have their blood tested. However, rather than testing

matrenka [14]

Answer: Expected number of tests = 5.013

Step-by-step explanation:

Define random variable X that marks the number of tests required for some certain

group. Observe that if the test is negative for all the people (which has probability 0.95), we make one and only one test. If some of the people is tested positive, we make ten additional tests for every person in that group separately. Hence, the expected number of tests will be for if they are all negative (1 test) and the case of at least one person testing positive (11 tests).

That Is,

E(X) = 1(0.95^10) + 11(1 - (0.95^10))

E(X) = 0.5987 + 4.414 = 5.013

8 0

4 years ago

Divide. Show your work.<br><br> (6x^4-5x^3+6x^2)/2x^2

serg [7]

We can do like we did before, distribute the denominator,

$\bf \cfrac{6x^4-5x^3+6x^2}{2x^2}\implies \cfrac{6x^4}{2x^2}-\cfrac{5x^3}{2x^2}+\cfrac{6x^2}{2x^2}\implies \cfrac{6}{2}\cdot \cfrac{x^4}{x^2}-\cfrac{5}{2}\cdot \cfrac{x^3}{x^2}+\cfrac{6}{2}\cdot \cfrac{x^2}{x^2}
\\\\\\
3 x^4x^{-2}-\cfrac{5}{2}x^3x^{-2}+3x^2x^{-2}\implies 3x^{4-2}-\cfrac{5}{2}x^{3-2}+3x^{2-2}
\\\\\\
3x^2-\cfrac{5}{2}x+3x^0\implies 3x^2-\cfrac{5}{2}x+3$

6 0

3 years ago

HELP! What is the equation? WILL GIVE BRAINLIEST! Picture attatched

lubasha [3.4K]

Answer:

y = -6x + 5

Step-by-step explanation:

Perpendicular to the line:

find reciprocal of slope 1/6 => m= -6

Sub m = -6 and point (-3,23) into equation of a line

y = mx + b

23 = -6(-3) + b

23 = 18 + b

Isolate and find b

b = 5

Sub slope and b to get the equation

8 0

3 years ago

Read 2 more answers

Find all solutions to the equation.

anyanavicka [17]

Answer:

$x=n\pi$ or $x= \frac{(2n\pm1)\pi}{2}$ , where $n\ge0$

Step-by-step explanation:

The given trigonometric equation is:

$(\sin x)(\cos x)=0$

By the zero product principle;

Either $\sin x=0$ or $\cos x=0$

When $\sin x=0$ , then $x=n\pi$

When $\cos x=0$ , then $x=2n\pi \pm \cos^{-1}(0)$

This implies that: $x=2n\pi \pm \frac{\pi}{2}$

Therefore the general solution is $x=n\pi$ or $x= \frac{(2n\pm1)\pi}{2}$ , where $n\ge0$

6 0

3 years ago

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Explain why segments connecting any pair of corresponding vertices of congruent pentagons are congruent. make a sketch to suppor

Veronika [31]

Answer:

Congruence between pentagons

Step-by-step explanation:

The relationship occurs because having two congruent Pentagons and generating a segment within them (or outside), congruence is extrapolated to the triangles generated within them. Thus, if there is congruence among the pentagons, it will exist between the formed triangles. In other words since the two pentagons are congruent, the corresponding angle pair is congruent. also the two corresponding side pairs are also congruent.

In the attached image for example, the ABCDE and KLMNO pentagons are congruent, so all of their internal division lines are also congruent (AC and KM)

8 0

3 years ago