Answer:
before you asked this question did you look it up
Step-by-step explanation:
Answer:
because either x-6=0 or x+1=0
x-6=0
x=0+6
x=6 OR,
x+1=0
x=0-1
x=-1
Step-by-step explanation:
Answer:
x=5 twice
Step-by-step explanation:
x^2-10x+25=0
multiply the coefficient of x^2 and the last term
1X25=25
find two numbers you can multiply to get 25 and add to get -10
-5 + (-5)=-10 the middle term
replace -10x with -5x -5x and solve the equation
x^2-5x-5x+25=0
factorise by grouping
x(x-5)-5(x-5)=0
(x-5)(x-5)=0
Either x-5=0,x=5 or x-5=0,x=5
Therefore x=5 twice.
Answer:
y = 4(x + 11)² - 484
Step-by-step explanation:
y = 4x² + 88x
factor the expression
y = 4(x² + 22x)
complete the square
y + ? = 4(x² + 22x + ?)
y + ? = 4(x² + 22x + 121)
add 4 • 121 to the left side
y + 4 • 121 = 4(x² + 22x + 121)
multiply
y + 484 = 4(x² + 22x + 121)
y + 484 = 4(x + 11)²
subtract both sides by 484
y = 4(x + 11)² - 484
Answer:
c(2) = -10
Step-by-step explanation:
The first equation says that the first term of the sequence is -20.
The second equation is saying that to find any term of the sequence, add 10 to the previous term.
c(2) = c(2-1) + 10
c(2) = c(1) + 10
c(2) = -20 + 10 = -10
