3 years ago

Please help me answer

Mathematics

1 answer:

marshall27 [118]3 years ago

3 0

Answer:

x=20

Step-by-step explanation:

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A rectangle has a length of x inches and a width 2 inches less than the length.If the dimensions were doubled, what would be the

zheka24 [161]

If the dimensions of the rectangle were doubled, the area in square inches is: $Area = 4x^2 - 8x$

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data:

Length = x inches

Width = x - 2 inches

If the dimensions of the rectangle were doubled, the value of L and W becomes;

$L = 2x$

$W = 2(x - 2)$

Mathematically, the area of a rectangle is given by the formula;

$Area = Length$ × $Width$

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$Area = 4x^2 - 8x$ square inches.

Find more information: brainly.com/question/897975

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3 years ago