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2 years ago

Select the correct answer.

Mathematics

1 answer:

liraira [26]2 years ago

4 0

Answer:

c and d

Step-by-step explanation:

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Consider f and c below. f(x, y, z) = (y2z + 2xz2)i + 2xyzj + (xy2 + 2x2z)k,

qaws [65]

$\dfrac{\partial f}{\partial x}=y^2z+2xz^2$
$f(x,y,z)=xy^2z+x^2z^2+g(y,z)$

$\dfrac{\partial f}{\partial y}=2xyz+\dfrac{\partial g}{\partial y}=2xyz$
$\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$\dfrac{\partial f}{\partial z}=xy^2+2x^2z+\dfrac{\mathrm dh}{\mathrm dz}=xy^2+2x^2z$
$\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=0$

$\implies f(x,y,z)=xy^2z+x^2z^2+C$

8 0

3 years ago

A square garden has 49 square feet. So the perimeter of the garden must be----feet.

lianna [129]

The side length of a square is the square root of the area:

Side length = √49 = 7 feet.

The perimeter of a square is 4s = 4*7 = 28 feet.

7 0

2 years ago

Read 2 more answers

Luke is swimming in still water at a constant speed of 3 meters/second.

STALIN [3.7K]

Answer:

1. velocity

Step-by-step explanation:

that is the answer above

4 0

2 years ago

A circular merry-go-round has a radius of 5 feet. Find the distance of a spin of one full rotation. Use 3.14 for pi and round th

Sedbober [7]

Option C

The distance of a spin of one full rotation is 31.4 feet

Solution:

Given that,

A circular merry-go-round has a radius of 5 feet

Radius = 5 feet

We have to find the distance of spin for one full rotation

Distance covered in 1 full of rotation is equal to circumference of circle

The circumference of circle is given as:

$C = 2 \pi r$

Where "r" is the radius

$C = 2 \times 3.14 \times 5\\\\C = 6.28 \times 5\\\\C = 31.4$

Thus the distance of a spin of one full rotation is 31.4 feet

6 0

3 years ago

If f(x)=x/2+8what if f(x) when x=10

Zinaida [17]

Answer:

f(10)=13

Step-by-step explanation:

f(x)=x/2+8

Let x = 10

f(10)=10/2 +8

= 5 + 8

= 13

5 0

3 years ago

Read 2 more answers