The value of 3 in 6300<span> is </span>10<span> times the value of 3 in </span>530.
<span>It's because 3 in 530 is tens and 3 in 6300 is hundreds.</span>
The answer is -5(x+6y+10)
Answer:
2 times
Step-by-step explanation:
the length and breadth of the parallelogram will be l and b, respectively.
Then, perimeter = 2(1 + b) [∵ perimeter of parallelogram = 2 x (length + breadth)]
If both sides are increased twice, then new length and breadth will be 21 and 2b, respectively.
Now, new perimeter = 2(21 + 2b) = 2 x 2(l + b) = 2 times of original perimeter.
the perimeter of parallelogram will be increased 2 times.
Answer:
-(x+14)/2
Step-by-step explanation:
There is a website that automatically calculates this for you.
Check it out, its called symbolab
<span>Shaded region is when x is negative</span>