Question

The slope of diagonal OA is ? and its equation is ?

Answer 1

Answer:

Slope = $\frac{4}{3}$

Equation of the line → $y=\frac{4}{3}x$

Step-by-step explanation:

Let the equation of diagonal OA is,

y = mx + b

Here, m = Slope of the line OA

b = y-intercept

Slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

m = $\frac{y_2-y_1}{x_2-x_1}$

Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,

m = $\frac{4-0}{3-0}$

m = $\frac{4}{3}$

Since, line OA is passing through the origin, y-intercept will be 0.

Therefore, equation of OA will be,

$y=\frac{4}{3}x$