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astraxan [27]
3 years ago
14

Which of these polygons do not belong a square a triangle a hexagon or a rectangle

Mathematics
1 answer:
Vesna [10]3 years ago
6 0
Hexagon does not belong
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Another fair dice is rolled 300 times. How many times would you expect it to land with a multiple of three on top? I need help t
ira [324]

Answer:

100 times

Step-by-step explanation:

multiples of 3 on a number cube are 3 and 6

probability of rolling a '3' or '6' is 1/6 + 1/6 = 2/6 or 1/3

1/3 x 300 = 100

7 0
3 years ago
Please help me with this problem please?
Alex

Answer:

Lily would spend on each type of activity would be 222 minutes.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The area of a door is 3024 square inches. If
olasank [31]

Answer:

Lets take all factors into consideration first

The door is a rectangle and the area of a rectangle is length times width

Let the width be w

Let the length be l

Equation length × breadth = area

(w+48)w = 3024

w^2 + 48w = 3024

w^2 + 48w - 3024 = 0

w^2 + 84w - 36w - 3024 = 0

w(w + 84) -36 ( w + 84) = 0

(w + 84) (w - 36) = 0

w + 84 = 0 AND w - 36 =0

w = -84 and w = 36

Since width cannot be negative, the right answer is 36

How did I get 84 and 36? Well, I had to factorize 3024 and since 84 times 36 is 3024 and 84 minus 36 is 48, I chose them.

7 0
3 years ago
Identify the restrictions on the domain of f(x) = x+2/x-3<br> x≠-2<br> x≠2<br> x≠-3<br> x≠3
erma4kov [3.2K]

Answer:

  x ≠ 3

Step-by-step explanation:

The denominator of ...

  f(x) = (x+2)/(x -3)

is zero when x=3, so the function is not defined there. Values of x for which the function is not defined are not part of the domain.

The restriction is: x ≠ 3.

_____

Please note that parentheses are required around numerators and denominators when a rational function is written in plain text. When it is typeset:

  f(x)=\dfrac{x+2}{x-3}

the division bar serves as a grouping symbol. In plain text, we cannot tell where numerator and denominator begin and end unless some other grouping symbol (parentheses) is used.

4 0
3 years ago
3/8x + 6(x+3) = -5(1/4x - 1) + 6x find the solution pls
umka21 [38]

Answer:

x = -8

Step-by-step explanation:

Solve for x:

(3 x)/8 + 6 (x + 3) = 6 x - 5 (x/4 - 1)

Hint: | Put the fractions in x/4 - 1 over a common denominator.

Put each term in x/4 - 1 over the common denominator 4: x/4 - 1 = x/4 - 4/4:

(3 x)/8 + 6 (x + 3) = 6 x - 5 x/4 - 4/4

Hint: | Combine x/4 - 4/4 into a single fraction.

x/4 - 4/4 = (x - 4)/4:

(3 x)/8 + 6 (x + 3) = 6 x - 5(x - 4)/4

Hint: | Put the fractions in (3 x)/8 + 6 (x + 3) over a common denominator.

Put each term in (3 x)/8 + 6 (x + 3) over the common denominator 8: (3 x)/8 + 6 (x + 3) = (3 x)/8 + (48 (x + 3))/8:

(3 x)/8 + (48 (x + 3))/8 = 6 x - (5 (x - 4))/4

Hint: | Combine (3 x)/8 + (48 (x + 3))/8 into a single fraction.

(3 x)/8 + (48 (x + 3))/8 = (3 x + 48 (x + 3))/8:

(3 x + 48 (x + 3))/8 = 6 x - (5 (x - 4))/4

Hint: | Distribute 48 over x + 3.

48 (x + 3) = 48 x + 144:

(48 x + 144 + 3 x)/8 = 6 x - (5 (x - 4))/4

Hint: | Group like terms in 48 x + 3 x + 144.

Grouping like terms, 48 x + 3 x + 144 = (3 x + 48 x) + 144:

((3 x + 48 x) + 144)/8 = 6 x - (5 (x - 4))/4

Hint: | Add like terms in 3 x + 48 x.

3 x + 48 x = 51 x:

(51 x + 144)/8 = 6 x - (5 (x - 4))/4

Hint: | Put the fractions in 6 x - (5 (x - 4))/4 over a common denominator.

Put each term in 6 x - (5 (x - 4))/4 over the common denominator 4: 6 x - (5 (x - 4))/4 = (24 x)/4 - (5 (x - 4))/4:

(51 x + 144)/8 = (24 x)/4 - (5 (x - 4))/4

Hint: | Combine (24 x)/4 - (5 (x - 4))/4 into a single fraction.

(24 x)/4 - (5 (x - 4))/4 = (24 x - 5 (x - 4))/4:

(51 x + 144)/8 = (24 x - 5 (x - 4))/4

Hint: | Distribute -5 over x - 4.

-5 (x - 4) = 20 - 5 x:

(51 x + 144)/8 = (24 x + 20 - 5 x)/4

Hint: | Combine like terms in 24 x - 5 x + 20.

24 x - 5 x = 19 x:

(51 x + 144)/8 = (19 x + 20)/4

Hint: | Make (51 x + 144)/8 = (19 x + 20)/4 simpler by multiplying both sides by a constant.

Multiply both sides by 8:

(8 (51 x + 144))/8 = (8 (19 x + 20))/4

Hint: | Cancel common terms in the numerator and denominator of (8 (51 x + 144))/8.

(8 (51 x + 144))/8 = 8/8×(51 x + 144) = 51 x + 144:

51 x + 144 = (8 (19 x + 20))/4

Hint: | In (8 (19 x + 20))/4, divide 8 in the numerator by 4 in the denominator.

8/4 = (4×2)/4 = 2:

51 x + 144 = 2 (19 x + 20)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

51 x + 144 = 38 x + 40

Hint: | Move terms with x to the left hand side.

Subtract 38 x from both sides:

(51 x - 38 x) + 144 = (38 x - 38 x) + 40

Hint: | Combine like terms in 51 x - 38 x.

51 x - 38 x = 13 x:

13 x + 144 = (38 x - 38 x) + 40

Hint: | Look for the difference of two identical terms.

38 x - 38 x = 0:

13 x + 144 = 40

Hint: | Isolate terms with x to the left hand side.

Subtract 144 from both sides:

13 x + (144 - 144) = 40 - 144

Hint: | Look for the difference of two identical terms.

144 - 144 = 0:

13 x = 40 - 144

Hint: | Evaluate 40 - 144.

40 - 144 = -104:

13 x = -104

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 13 x = -104 by 13:

(13 x)/13 = (-104)/13

Hint: | Any nonzero number divided by itself is one.

13/13 = 1:

x = (-104)/13

Hint: | Reduce (-104)/13 to lowest terms. Start by finding the GCD of -104 and 13.

The gcd of -104 and 13 is 13, so (-104)/13 = (13 (-8))/(13×1) = 13/13×-8 = -8:

Answer: x = -8

5 0
3 years ago
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