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serg [7]
3 years ago
11

CAN SOMEONE HELP ME FAST?

Mathematics
1 answer:
maksim [4K]3 years ago
4 0

Answer:

221.38

Step-by-step explanation:

i hope this is helpful for you

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Please help really I need it thank you :)
tamaranim1 [39]

Answer:

44, 6, and 24 are not perfect square

Step-by-step explanation:

Perfect square are numbers that can be square rooted with a result of a perfect whole number.

√16=4

√44= 6.63324...

√81= 9

√6= 2.44948...

√49= 7

√24= 4.898997...

6 0
2 years ago
Automobile racing, high-performance driving schools, and driver education programs run by automobile clubs continue to grow in p
yuradex [85]

Answer:

Step-by-step explanation:

Hello!

Given the variables

X₁: Weight of a safety helmet for racers

X₂: Price of a safety helmet for racers

Note, there is n= 17 observed values for each variable so for all calculations I'll use this number and disregard the 18 mentioned in the text.

a) Scatterplot in attachment.

b) If you look at the diagram it seems that there is a negative linear regression between the price and the weight of the helmets, meaning, the higher the helmet weights, the less it costs.

c) The estimated regression equation is ^Yi= a + bXi

n= 17; ∑Y= 6466; ∑Y²= 3063392; ∑X= 1008; ∑X²= 60294; ∑XY= 367536

Y[bar]= 380.35; X[bar]= 59.29

b= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} } = \frac{367536-\frac{1008*6466}{17} }{60294-\frac{(1008)^2}{17} } = -30.18

a= Y[bar]- bX[bar]= 380.35-(-30.18)*59.29= 2169.77

The estimated regression equation for the price of the helmets as a function of their weight is:

^Yi= 2169.77 -30.18Xi

I hope it helps!

8 0
3 years ago
If log2 5 = k, determine an expression for log32 5 in terms of k.
lukranit [14]

Answer:

log_3_2(5)=\frac{1}{5} k

Step-by-step explanation:

Let's start by using change of base property:

log_b(x)=\frac{log_a(x)}{log_a(b)}

So, for log_2(5)

log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)

Now, using change of base for log_3_2(5)

log_3_2(5)=\frac{log(5)}{log(32)}

You can express 32 as:

2^5

Using reduction of power property:

log_z(x^y)=ylog_z(x)

log(32)=log(2^5)=5log(2)

Therefore:

log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)

As you can see the only difference between (1) and (2) is the coefficient \frac{1}{5} :

So:

\frac{log(5)}{log(2)} =k\\

log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k

6 0
3 years ago
.
Sholpan [36]

Answer:

Larry must mow approximately 25 lawns before he starts making a profit

Step-by-step explanation:

8 0
3 years ago
Suppose f '' is continuous on (−[infinity], [infinity])
Angelina_Jolie [31]

Answer with Step-by-step explanation:

We are given that a function f(x) is continuous on (-\infty,\infty).

1.f'(-1)=0 and f''(-1)=-7

We have to find information about f.

When f'(-1)=0 and f''(-1)=-7 < 0

Then, function is maximum at x=-1.

Therefore, at x=-1, f has local maximum.

Answer:a)at x=-1 ,f has local maximum.

2.) if f'(4)=0 and f''(4)=0

We know that when f''(x)=0 then test fails  then the function has not maximum or minimum.

Therefore, at x=4 , f has not a maximum or minimum.

Answer:c) at x=4, f has not a maximum or minimum.

4 0
3 years ago
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