What 3D figure is a paper towel carboard tube?

Mathematics

1 answer:

Roman55 [17]3 years ago

4 0

Answer:

An 11 inch tall roll of paper towels has an inner cardboard tube with a diameter of 1.5 inches.

Step-by-step explanation:

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The following table shows the salary of 7 people in an office last year.

Ede4ka [16]

Answer:

Mean of worker's salary = £27,785.71 (Approx.)
Mean of worker's salary[Excluding Deva's income] = £16,500 (Approx.)

Step-by-step explanation:

Given:

Total number of worker = 7

Find;

1] Mean of worker's salary

2] Mean of worker's salary[Excluding Deva's income]

Computation:

Mean = Sum of all observation / Total number of observation

1] Mean of worker's salary = [13,500 + 27,500 + 13,750 + 79,000 + 18,750 + 27,500 + 15,000] / 7

Mean of worker's salary = [194,500] / 7

Mean of worker's salary = £27,785.71 (Approx.)

2] Mean of worker's salary[Excluding Deva's income] = [13,500 + 27,500 + 13,750 + 18,750 + 27,500 + 15,000] / 6

Mean of worker's salary[Excluding Deva's income] = [115,500]/7

Mean of worker's salary[Excluding Deva's income] = £16,500 (Approx.)

3 0

3 years ago

Please help with this graph ‼️

svlad2 [7]

Considering f(x)= y. You find what y value correlates with the x value so f(0)=4 brong that the line with y=4 the x is 0. f(-2)= 2 as the line where x=-2 has y=2

3 0

3 years ago

Read 2 more answers

Write a formula for function f in terms of function g.

emmasim [6.3K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

so hmm if you notice, your f(x) there, looks just like g(x), but is "shifted horizontally" by about 9 units to the right

that simply means, based on that template above, that C/B = -9, and we can simply make B = 1 and C = -9, and we get C/B = -9/1 which is -9

thus $\bf \begin{array}{llcll}
f(x)=g(&1x&-9)\\
&\uparrow &\uparrow \\
&B&C
\end{array}\iff f(x)=g(x-9)$