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ivolga24 [154]
3 years ago
9

Which set of rectangular coordinates describes the same location as the polar coordinates (4,pi)?

Mathematics
2 answers:
Nuetrik [128]3 years ago
8 0

Answer:

(-4,0)

Step-by-step explanation:

Nataly [62]3 years ago
6 0

\bf (\stackrel{r}{4}~,~\stackrel{\theta }{\pi })\qquad \begin{cases} x=&rcos(\theta )\\ &4cos(\pi )\\ &4(-1)\\ &-4\\ y= &rsin(\theta )\\ &4sin(\pi )\\ &4(0)\\ &0\\ \end{cases}\qquad \implies (\stackrel{x}{-4}~,~\stackrel{y}{0})

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What’s the work and answer for this? Someone please tell me
Arturiano [62]

Answer:  14

Step-by-step explanation:

We arrange the number as -3,  1, 7, 8, 18, 19, 42, the old median is 8.

But the median has change to 11 when the number is add, which means that the number is between 7 and 18.

(8 + x)/2 = 11      Where x is the new number

8 + x = 22

x = 14

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Find the value of x in the isosceles trapezoid if AC = 2x + 2 and DB = 4x - 6
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mrs_skeptik [129]

Answer:

322 ft²

Step-by-step explanation:

Trapezoid area formula:

A=\frac{a+b}{2} *h

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a = 11

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h = 14

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A=\frac{a+b}{2} *h\\\\A=\frac{11+35}{2} *14\\\\A=\frac{46}{2} *14\\\\A=23*14\\A=322

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5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. How old are Nuri n Sonu?​
Papessa [141]

Answer:

Answer will be 50

Step-by-step explanation:

Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.

Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,

Five years ago,

Nuri’s age = x-5 years

Sonu’s age = y-5 years

And relation between ages can be given as

Nuri’s age = 3×sonu’s age or

x-5 = 3(y-5)

x-5 = 3y-15

x-3y+10 = 0 ………..(i)

Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.

So, ten years ago,

Nuri’s Age = x+10

Sonu’s Age = y+10

And relation between ages can be written as

x+10 = 2(y+10)

x+10 = 2y+20

x-2y-10 = 0 …………..(ii)

Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.

Value of ‘x’ from equation (i) be

x = 3y-10 ……….(iii)

Putting value of ‘x’ from equation (iii) in equation (ii) we get,

3y-10-2y-10 = 0

y = 20

Now, from equation (iii) value of ’x’ can be given as,

x= 3(20)-10

x = 50

Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.

7 0
2 years ago
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