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lora16 [44]
3 years ago
7

In order to write the equation of the line passing through the point (-2, 2) that is parallel to the line y = 2x + 3 , the next

step is to find the y-intercept of the perpendicular line. What is the y-intercept of the perpendicular line through point (-2, 2)?
Mathematics
2 answers:
OlgaM077 [116]3 years ago
6 0

Answer:

Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6.

Anettt [7]3 years ago
6 0

Answer:

See below.

Step-by-step explanation:

This question makes no sense.

Here is the question. Pay attention to the words in boldface.

"In order to write the equation of the line passing through the point (-2, 2) that is parallel to the line y = 2x + 3 , the next step is to find the y-intercept of the perpendicular line. What is the y-intercept of the perpendicular line through point (-2, 2)?"

Is the question asking for the parallel line or the perpendicular line?

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For a moving object, the force acting on the object varies directly with the objects acceleration. When a force of 35 N acts on
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<h3>Answer:  3 m/s^2</h3>

=======================================================

According to Newton's Second Law, we know that

F = m*a

where F is the force applied, m is the mass and 'a' is the acceleration.

We see that this is a direct variation equation for F and a, such that m is the constant of variation. It's similar to how y = kx is also a direct variation equation.

Plug in F = 35 and a = 5 to find m

F = ma

35 = m*5

35/5 = m

7 = m

m = 7

The object has a mass of 7 kg

Our equation F = ma updates to F = 7a

Now plug in the force F = 21 to find 'a'

F = 7a

21 = 7a

21/7 = a

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The acceleration will be 3 m/s^2

Notice how a smaller force applied means that the acceleration has also gone down as well.

8 0
3 years ago
Two equations are given below:
Sindrei [870]
\left \{ {{a - 3b = 16} \atop {a = b - 2}} \right.  \\  \\  \left \{ {{a = 16 + 3b} \atop { 16 + 3b = b - 2}} \right.  \\  \\  \left \{ {{a = 16 + 3b} \atop {3b - b = - 2 - 16}} \right.  \\  \\  \left \{ {{a =16 + 3b} \atop {2b  = -18}} \right.  \\  \\  \left \{ {{a=16 + 3b} \atop {b=-9}} \right.  \\  \\  \left \{ {{a=16 + 3b = 16 + 3*(-9) = 16 - 27 = -11} \atop {b=-9}} \right.

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8 0
3 years ago
the length of a rectangle is 5 inches longer than twice the width and the area is 12 inches squared. Let l represent the length
svet-max [94.6K]

Answer:

Length = 8 inch , Width = \frac{3}{2} , This equation models the situation

Step-by-step explanation:

Given as ;

The Area of Rectangle is 12 inches²

The Length of Rectangle is 5 inches longer than twice the width

Let The Length = L inches

      The Width   = W inches

According to question ,

L = 5 + (2 × w )

∵ The Area of Rectangle = Length × width

Or, 12  inches²  = [ 5 + (2 × w ) ] ×  w

Or,  12  inches² = 5 w +2 w²

Or,  2 w² + 5 w  - 12 = 0

Or,   2 w² + 8 w  -3 w - 12 = 0

Or,  2 w (w +4) - 3 (w + 4) = 0

I.e (w + 4) ( 2 w - 3) = 0

So ,  w = -4 , and w = \frac{3}{2}

∴  Length = 5 + (2 × w ) =

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so ,  L = 5 + 3 = 8

Hence Length = 8 inch , Width = \frac{3}{2}   This equation models the situation Answer

3 0
3 years ago
Solve for x: 2x^2 + 3x = 2 <br>solving other quadratic equation by factoring ​
DIA [1.3K]

Answer: x=1/2,-2

not sure if that is what you need

Step-by-step explanation:

7 0
3 years ago
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vesna_86 [32]

Answer:

C.  

x + 0.05x = 3.15, which has one solution

Step-by-step explanation:

Let x = the price Joshua pays for the pack of pens

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That is x* .05

The new cost is 3.15

x+.05x = 3.15

This will have one solution

3 0
4 years ago
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