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Radda [10]
3 years ago
6

Help as soon as possible

Mathematics
1 answer:
Maurinko [17]3 years ago
6 0

Answer:

Step-by-step explanation:

I am sorry but please give detailed question

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What is the circumference of a circle with an area of 200.96 cm??
Viefleur [7K]

Answer:

circumference is 50.24cm

Step-by-step explanation:

πr^{2} = 200.96

r = \sqrt{200.96/\pi } = \sqrt{200.96/3.14}=8

Circumference = 2πr = 2 x.3.14.x 8 = 50.24

4 0
3 years ago
The equation of the linear regression line represents the relationship between the number of years since 2000, x, and the averag
Readme [11.4K]
The regression equation is in the form y = mx+b where m = 938 is the slope

The slope of 938 means that each year the tuition is increasing by roughly $938.

The answer is choice C.
7 0
3 years ago
Write out the sample space for the given experiment. Use the following letters to indicate each choice: M for mushrooms, A for a
MrMuchimi

Answer: {(MBV), (MBH) , (MEV) , (MEH) , (OBV), (OBH) , (OEV) , (OEH)}

Step-by-step explanation:

  • Sample space is a set that contains all the possible outcomes for an event.

For salad:

Choices for extra toppings (mushrooms, olives) =2

Choices for meats (bacon, eggs) =2

Choices for dressings (vinaigrette, honey mustard.)= 2

By Fundamental counting principal .

The number of different salads can be made= (Choices for extra toppings) x (Choices for meats ) x (Choices for dressings)

= 2 x 2 x 2 = 8

All the possible outcomes = (MBV), (MBH) , (MEV) , (MEH) , (OBV), (OBH) , (OEV) , (OEH)

Required Sample space would be : {(MBV), (MBH) , (MEV) , (MEH) , (OBV), (OBH) , (OEV) , (OEH)}

5 0
2 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).
Dvinal [7]
<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:


..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation:  , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B14%7D%20%2F%20%5Cfrac%7B4%7D%7B3%7D" id="TexFormula1" title="\frac{9}{14} / \
Assoli18 [71]
About 0.482
calculator
6 0
3 years ago
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