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3 years ago

What is 90% of 1,000,000?

Mathematics

1 answer:

vovangra [49]3 years ago

5 0

you're welcome, and I hope this helps

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Help me out please !!!!

Brums [2.3K]

Answer:

0.06 liters

Step-by-step explanation:

acid concentration of 65% means that it of 100 units of that solution 65 are acid, and the remaining 35 are water.

so, 100 units are 0.2 liters in this example.

that means that 65/100 × 0.2 = 0.13 liters are acid.

35/100 × 0.2 = 0.07 liters are water

we get a 50% concentration, when we have the same amount of water and acid in the solution (acid is only half of 50% of the solution).

the account of acid remains the same, as we are only adding water.

so, how much water do we need to get from 0.07 liters to 0.13 liters (the same as the already present acid) ?

0.13 - 0.07 = 0.06 liters

4 0

3 years ago

Which explanation provides the best real-world scenario of the graph?

Naddika [18.5K]

The last one is the only one that makes sense according to the standard position function. -16t^2 is the pull of gravity on an object in free fall, and the height is 120 feet above the ground. Hopefully that's what you need since there's no graph we can refer to

5 0

4 years ago

Read 2 more answers

40% of what number is 18?

vladimir1956 [14]

Answer:

40 percent (calculated percentage %) of what number equals 18? Answer: 45.

3 0

3 years ago

Read 2 more answers

Hello can you please help me posted picture of question

vagabundo [1.1K]

We are to select 2 people to sit in first row from 6.

This is a problem of Combinations. We are find permutation of 6 people taken 2 at a time. This can be represented as 6C2.

$6C2= \frac{6!}{4!*2!} \\ \\=15$

So, the answer is option B

7 0

3 years ago

Now suppose that bigger cups are ordered and the machine’s mean amount dispensed is set at μ=12. Assuming we can precisely adjus

Elina [12.6K]

Answer:

σ should be adjusted at 0.5.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean 12.

Assuming we can precisely adjust σ, what should we set σtobe so that the actual amount dispensed is between 11 and 13 ounces, 95% of the time?

13 should be 2 standard deviations above the mean of 12, and 11 should be two standard deviations below the mean.

So 1 should be worth two standard deviations. Then

$2\sigma = 1$

$\sigma = \frac{1}{2}$

$\sigma = 0.5$

σ should be adjusted at 0.5.

4 0

3 years ago