this formula, doesn't rely on a product, relies on a "sum", or is namely an arithmetic sequence, aₙ₋₁ -3 is another way of saying, the value of the previous term minus 3, so it relies on the ordinal value of a term, so is an recursive formula, well, let's get it when n = 4.

$\begin{array}{ccll} order&term&value\\ \cline{1-3} 1&a_1&8\\ 2&a_2&a_{2-1}-3\\ &&a_1-3\\ &&8-3\\ &&5\\ 3&a_3&a_{3-1}-3\\ &&a_2-3\\ &&2\\ 4&a_4&a_{4-1}-3\\ &&a_3-3\\ &&2-3\\ &&-1 \end{array}$

5 0

2 years ago

(4 + 7w2)

ivanzaharov [21]

Answer: 18w^2 - 6w + 4

Explanation:

(4 + 7w^2) - (6w - 11w^2)
= 4 + 7w^2 - 6w + 11w^2
= 18w^2 - 6w + 4

5 0

2 years ago

Simplify completely 25 w to the sixth power over 10 w to the third power divided by 30 w squared over 5 w.

malfutka [58]

$\cfrac{25w^6}{10w^3}: \cfrac{30w^2}{5w}= \cfrac{5w^3}{2}* \cfrac{5w}{30w^2}= \cfrac{w}{2}* \cfrac{5w}{6}= \cfrac{5w^2}{12}$

4 0

3 years ago

Read 2 more answers

Find a ratio equivalent to 15/60

Flauer [41]

Answer:

$\large\boxed{\dfrac{15}{60}=\dfrac{5}{20}=\dfrac{3}{12}=\dfrac{1}{4}}$

$\large\boxed{\dfrac{15}{60}=\dfrac{30}{120}=\dfrac{45}{180}=\dfrac{60}{240}}$

Step-by-step explanation:

Divide the numerator and the denominator by the same number:

$\dfrac{15}{60}\\\\=\dfrac{15:5}{60:5}=\dfrac{3}{12}\\\\=\dfrac{15:3}{60:3}=\dfrac{5}{20}\\\\=\dfrac{15:15}{60:15}=\dfrac{1}{4}\\\vdots$

Multiply the numerator and the denominator by the same number:

$\dfrac{15}{60}\\\\=\dfrac{15\cdot2}{60\cdot2}=\dfrac{30}{120}\\\\=\dfrac{15\cdot3}{60\cdot3}=\dfrac{45}{180}\\\\=\dfrac{15\cdot4}{60\cdot4}=\dfrac{60}{240}\\\vdots$

7 0

2 years ago

Read 2 more answers