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3 years ago

An object is launched straight up into the air at an initial velocity of 64 feet per

Mathematics

1 answer:

alexandr1967 [171]3 years ago

4 0

Answer:

sorry but i don't know the answer hut hopefully you will get an answer

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Chrissy wants to spend at most $45 on dinner. If she bought an entree for $20 and she wants to buy mini appetizers for $3 each,

Sever21 [200]

Answer:

Step-by-step explanation:

Chrissy can buy 8 mini appetizers.......because

45 - 20 = 25

25 divide 3 = 8.3333333333333 so the most she can buy is 8..

8 0

3 years ago

Volume of sun is 1.4×10^18 and volume of earth is 1.1×10^12 how many earth can fit in the sun

Advocard [28]

$\frac{1.4\cdot10^{18}}{1.1\cdot10^{12}}=
1.(27)\cdot10^6=1272727.(27)$

$1272727 \hbox{ Earths}$

6 0

3 years ago

How many edges does a cube has? A.10 B 12 C 14 D 16

Serga [27]

B. 12 would be your answer

7 0

3 years ago

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Which is the slope of the line that passes through the points (4,2) and (6,7)

Anastasy [175]

The slope is 5/2. You can find the slope by using y2-y1/x2-x1. 7-2/6-4= 5/2.

5 0

4 years ago

Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro

Elanso [62]

Answer:

Choose the first alternative

$\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}$

Step-by-step explanation:

Probabilities

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions $(N_s)$ and the total number of possible choices $(N_t)$ , i.e.

$\displaystyle P=\frac{N_s}{N_t}$

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

$_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}$

The total number of possible choices is

$_{2}^{20}\textrm{C} \text{ ways to do it}$

The probability is then

$\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}$

Choose the first alternative

7 0

3 years ago

Read 2 more answers