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3 years ago

Volume of sun is 1.4×10^18 and volume of earth is 1.1×10^12 how many earth can fit in the sun

Mathematics

1 answer:

Advocard [28]3 years ago

6 0

$\frac{1.4\cdot10^{18}}{1.1\cdot10^{12}}=
1.(27)\cdot10^6=1272727.(27)$

$1272727 \hbox{ Earths}$

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A jet travels 2301 miles against the wind in 3 hours and 2811 miles with the wind in the same amount of time. What is the rate o

astraxan [27]

Answer:

The rate of the jet in still air is 852 miles per hour. The rate of the wind is 85 miles per hour.

Step-by-step explanation:

Let suppose that jet travels uniformly, that is, at constant speed, the expressions for its travels against the wind and with the wind are, respectively:

Against the wind

$v -u = \frac{\Delta x_{1}}{\Delta t_{1}}$

With the wind

$v +u = \frac{\Delta x_{2}}{\Delta t_{2}}$

Where:

$v$ - Speed of the jet in still air, measured in miles per hour.

$u$ - Speed of wind, measured in miles per hour.

$\Delta x_{1}$ , $\Delta x_{2}$ - Distances travelled by jet against the wind and with the wind, measured in miles.

$\Delta t_{1}$ , $\Delta t_{2}$ - Times against the wind and with the wind, measured in hours.

By adding both expressions:

$2\cdot v = \frac{\Delta x_{1}}{\Delta t_{1}}+\frac{\Delta x_{2}}{\Delta t_{2}}$

$v = \frac{1}{2}\cdot \left(\frac{\Delta x_{1}}{\Delta t_{1}} + \frac{\Delta x_{2}}{\Delta t_{2}} \right)$

Given that $\Delta x_{1} = 2301\,mi$ , $\Delta t_{1} = 3\,h$ , $\Delta x_{2} = 2811\,mi$ and $\Delta t_{2} = 3\,h$ , the speed of the jet is:

$v = \frac{1}{2}\cdot \left(\frac{2301\,mi}{3\,h}+\frac{2811\,mi}{3\,h} \right)$

$v = 852\,\frac{mi}{h}$

The rate of the jet in still air is 852 miles per hour.

Lastly, the rate of the wind is:

$u = \frac{\Delta x_{2}}{\Delta t_{2}}-v$

$u = \frac{2811\,mi}{3\,h}-852\,\frac{mi}{h}$

$u = 85\,\frac{mi}{h}$

The rate of the wind is 85 miles per hour.

5 0

3 years ago

In analyzing hits by certain bombs in a war, an area was partitioned into 553 regions, each with an area of 0.95 km2. A total

Leto [7]

Answer:

Probability of having two hits in the same region = 0.178

mu: average number of hits per region

x: number of hits

e: mathematical constant approximately equal to 2.71828.

Step-by-step explanation:

We can describe the probability of k events with the Poisson distribution, expressed as:

$P(x=k)=\frac{\mu^ke^{-\mu}}{k!}$

Being μ the expected rate of events.

If 535 bombs hit 553 regions, the expected rate of bombs per region (the events for this question) is:

$\mu=\frac{\#bombs}{\#regions} =\frac{535}{553}= 0.9674$

For a region to being hit by two bombs, it has a probability of:

$P(x=2)=\frac{\mu^2e^{-\mu}}{2!}=\frac{0.9674^2e^{-0.9674}}{2!}=\frac{0.9359*0.38}{2}=0.178$

4 0

3 years ago

Which expression can be used to solve 3/5 divided by 7/10

inna [77]

Answer:

.6/.7

Step-by-step explanation:

4 0

3 years ago

Juan starts walking at 4 miles per hour. An hour and a half later, Cathy starts jogging along the same route at 7 miles per hour

kifflom [539]

Answer:

The answer to your question is 2 hours

Step-by-step explanation:

Data

Juan speed = 4 mi/h

Cathy speed = 7 mi/h

t = x

Formula

speed = distance/time

Solve for distance

distance = speed x time

d = s x t

Distance travelled by Juan

d = 4t

Distance travelled by Juan in 1.5 h

d = 4(1.5)

d = 6 mi

total distance d = 6 + 4t

Distance travelled by Cathy

d = vt

d = 7t

Equal both equations

6 + 4t = 7t

Solve for t

6 = 7t - 4t

6 = 3t

6/3 = t

2 = t

Cathy wll catch up with Juan in 2 hours

6 0

4 years ago

Read 2 more answers

I just need #2 <br><br> thanks for giving your time to help me

SVEN [57.7K]

2.
1099.99x 0.58 =637.9942
1099.99-637.9942= 461.9958
461.9958x 0.065=30.029727
461.9958-30.029727=431.967073

The answer round is 431.96

3.
42.95x1/5= 8.59
42.95-8.59 = 34.56
34.56 x 0.07=2.4192
34.56-2.4192= 32.1408
Round it is 32.14

4.
1250x0.85= 1062.5
1250-1062.5 =187.5

7 0

3 years ago