You are given a rectangle and are told that the length is 1 cm more than twice the width of the rectangle. The area of the rect. is also given, and is 21 cm^2.
Find the length and width. To do this, represent the length by y and the width by x. Then "1 cm more than twice the width" comes out to y=2x+1 (cm).
Since the area of a rect. is equal to the product of its length and width,
x(2x+1)=21 cm^2. Multiply out x(2x+1). show your work. Next, subtract 21 from both sides. Write your algebraic expression on the left side as a quadratic equation in standard form.
Solve this quadratic equation for x. Recall that x (in cm) will represent the width of the rect., and y=2x+1 (in cm) will repr. the length.
Step-by-step explanation:
3x + 5x - 2t = 8
3 . (-1) + 5 . (-1) - 2t = 8
-3 - 5 - 2t = 8
-8 - 2t = 8
-2t = 8 + 8
-2t = 16
t = 16/-2
t = -8
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Answer:
<Ber=<kem(vertically opposite angle)
9x-17=3x+31
9x-3x=31+17
6x=48
x=48/6=8
<kem=3×8+31=55°is answer
