Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
4
Because I took the test and got it correct.
Answer:
= - 282x
Step-by-step explanation:
- 6(14x - 23x + 56x)
= - 84x + 138x - 336x
= 54x - 336x
= - 282x
Does anyone wanna help me with something ill give u bloxburg (from ro _blox) money if u know how to do _it!And yes it’s math
Answer:
can be fourth one cause it starts at 2 on y axis. ( fourth option)
Step-by-step explanation:
can't be the first one cause it starts at origin
can't be second one cause it starts at -2 on x axis
can't be third on cause it starts on 2 on x axis
can't be fifth cause it starts on -2 on y axis.
