Find the value of x^2+1/x^2 when <br>x-1/x=3

If anyone is good at math and likes to help someone that is not good with it I will give you brainliest

hammer [34]

Answer:

1st pic answer:

Slope= -3

Parallel slope= -3

Perpendicular slope = 1/3

2nd pic answers:

1 and 2 are parallel

1 and 3 are perpendicular

2 and 3 are perpendicular

Step-by-step explanation:

To find the slope in your first equation (6x+2y=1) you need to get y alone so that your equation will be in slope-intercept form (y=mx+b).

6x+2y=1 Start by subtracting the 6x over to the other side.

-6x -6x

2y= -6x+1 Next divide by 2 to get y completely alone.

$\frac{2y}{2} =\frac{-6x}{2}+\frac{1}{2}$

y= -3x+1/2

So to answer the first part your slope is -3. Parallel slope would be the same as your regular slope. Perpendicular would be the opposite, so that means you have to flip it and change the sign.

-3 flipped is -1/3

if you change the sign it becomes positive giving you 1/3

Part 2

Your first step would be to get all the equations into the slope-intercept form (y=mx+b). The second one is already in the form so we only need to change 1 and 3.

3y=5x+2 To get y alone you need to divide everything by 3.

$\frac{3y}{3}=\frac{5x}{3} +\frac{2}{3}$

y=5/3x+2/3 Before we work on equation 3 we can go ahead and compare equations 1 and 2.

1: y= $\frac{5x}{3} +\frac{2}{3}$

2: y= $\frac{5x}{3} +7$ Since 1 and 2 have the same slope they would be parallel.

Now to change equation 3.

6x+10y=8 Start by subtracting the 6x over to the other side.

-6x -6x

10y=-6x+8 Now divide everything by 10 to get y alone.

$\frac{10y}{10}=\frac{-6x}{10} +\frac{8}{10}$

y=-6x/10+8/10 Now we need to simplify the fractions using common factors. I'm going to use 2 for both equations, so you take -6 and 10 both divided by 2, which gives you -3 and 5(-3x/5). Now do the same with the other fraction. 8 and 10 divided by 2 gives us 4 and 5 (4/5)

3: y= $\frac{-3x}{5}+\frac{4}{5}$

2: y= $\frac{5x}{3} +7$

1: y= $\frac{5x}{3} +\frac{2}{3}$

Since three has an opposite slope of both 1 and 2 it would be perpendicular to both.

5 0

3 years ago

Given:angleONL congruent to angleMLN, angleO and angleM are right angles.

Harrizon [31]

ok so hi im elizabeth can i help you

8 0

3 years ago

Please guys I am begging you to help me! This was due yesterday and I need help! SO please help!

jeka57 [31]

Answer:

Q3. 12 units
Q4. 6.33 units
Q5. 66.19°

Step-by-step explanation:

Q3

DE and DF are legs and EF is hypotenuse

DE = √EF² - DF²
DE = √13² - 5² = √169 - 25 = √ 144 = 12
DE = 12 units

Q4

PR is opposite side of angle Q and RQ is adjacent side

tan 54 = PR/RQ
tan 54 = PR / 4.6
PR = 4.6tan 54
PR = 6.33 units

Q5

As previous question, using tan as BC is opposite and AC is adjacent leg of angle A

tan A = 6.8/3
tan A = 2.266
A = arctan (2.266)
A = 66.19°

8 0

3 years ago

Evaluate.<br> 18.65 -52/11=

professor190 [17]

The answer is about 13.9927.

You would divide 52/11 and then subtract that decimal by 18.65.

18.65-4.7272=13.9927.

6 0

3 years ago

a scuba diver descended at a rate of 2 1/4 per second. If 0 represents the surface of the water and distances below the surface

Shtirlitz [24]

Answer:

The location will be at $- 28\frac{1}{8}$ units.

Step-by-step explanation:

A scuba diver descended at a rate of $2\frac{1}{4}$ units per second.

Now, if 0 represents the surface of the water and distances below the surface are negative, then after $12\frac{1}{2}$ seconds the location of the diver will be given by the followings :

In one second the diver descends by 2.25 units depth.

So, in 12.5 seconds the diver will descend by $(2.25 \times 12.5) = 28.125$ units i.e. $28\frac{1}{8}$ units depth.

Therefore, the location will be at $- 28\frac{1}{8}$ units. (Answer)

6 0

3 years ago

Find the value of x^2+1/x^2 when x-1/x=3​

Find the value of x^2+1/x^2 when x-1/x=3