There are 4 quadrants in a coordinate plane
- The starting point is in the second quadrant, while the finishing point is in the fourth quadrant.
- The starting point is a reflection of the checkpoint across the y-axis
<u>Part A</u>
The points are given as:
For the starting point, the x-coordinate is negative, while the y-coordinate is positive.
This implies that the starting point is in the second quadrant
For the finishing point, the x-coordinate is positive, while the y-coordinate is negative.
This implies that the finishing point is in the fourth quadrant
<u>Part B</u>
The checking point is given as:
The starting point is given as:
Notice that the y-coordinate of both points are the same, but the x-coordinates are negated.
This means that the starting point is a reflection of the checkpoint across the y-axis, and vice versa
Read more about quadrants at:
brainly.com/question/14061041
In base 12, A represents 10 and B represents 11. So
7B6A (base 12) = 7*12^3 + 11*12^2 + 6*12^1 + 10*12^0
7B6A (base 12) = 12,096 + 1,584 + 72 + 10
7B6A (base 12) = 13,762 (base 10)
Answer:
28.56 m²
Step-by-step explanation:
What we need to do for the quarter circle is use the following formula: 1/4(πr²)
(4 * 4) + 1/4(3.14 * 4²)
16 + 1/4(3.14 * 16)
16 + 1/4(50.24)
16 + 12.56
28.56 m²
The best approximation for the area of this figure is 28.56 m².
Answer:
- first side: 55 cm
- second side: 60 cm
- third side: 50 cm
Step-by-step explanation:
The problem statement gives all the side lengths in terms of that of the second side. Let s represent the length of the second side in cm. Then the length of the first side is (2s-65), and the length of the third side is (s-10). The perimeter is the sum of all the side lengths:
165 = (2s -65) +s +(s-10)
165 = 4s-75
240 = 4s
60 = s . . . . . . . . second side
2s-65 = 55 . . . . first side
s-10 = 50 . . . . . . third side
In order, the side lengths are 55 cm, 60 cm, 50 cm.
