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VLD [36.1K]
3 years ago
9

Algebra 2 Math. I need help please. Question is image.

Mathematics
1 answer:
AURORKA [14]3 years ago
7 0

Answer:

k = 8

(x² + 8)(x - 1)(x+5)

Step-by-step explanation:

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The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.4,
k0ka [10]

There are 4 quadrants in a coordinate plane

  • The starting point is in the second quadrant, while the finishing point is in the fourth quadrant.
  • The starting point is a reflection of the checkpoint across the y-axis

<u>Part A</u>

The points are given as:

Start = (-5.4,3)

Finish = (3,-5.4)

For the starting point, the x-coordinate is negative, while the y-coordinate is positive.

This implies that the starting point is in the second quadrant

For the finishing point, the x-coordinate is positive, while the y-coordinate is negative.

This implies that the finishing point is in the fourth quadrant

<u>Part B</u>

The checking point is given as:

Checking = (5.4,3)

The starting point is given as:

Start = (-5.4,3)

Notice that the y-coordinate of both points are the same, but the x-coordinates are negated.

This means that the starting point is a reflection of the checkpoint across the y-axis, and vice versa

Read more about quadrants at:

brainly.com/question/14061041

3 0
3 years ago
Read 2 more answers
Write 7B6A.<br> 7B6Atwelve<br> in the base-ten system.
Juli2301 [7.4K]

In base 12, A represents 10 and B represents 11. So

7B6A (base 12) = 7*12^3 + 11*12^2 + 6*12^1 + 10*12^0

7B6A (base 12) = 12,096 + 1,584 + 72 + 10

7B6A (base 12) = 13,762 (base 10)

7 0
4 years ago
7 x 4 - 20 <br> Answer this 2 mins later (timer on math probs)
xz_007 [3.2K]

Answer:

I think answer is 8.....

4 0
3 years ago
HELP!!!! A quarter circle is attached to the side of a square as shown.
Paul [167]

Answer:

28.56 m²

Step-by-step explanation:

What we need to do for the quarter circle is use the following formula: 1/4(πr²)

(4 * 4) + 1/4(3.14 * 4²)

16 + 1/4(3.14 * 16)

16 + 1/4(50.24)

16 + 12.56

28.56 m²

The best approximation for the area of this figure is 28.56 m².

6 0
3 years ago
A triangle has a perimeter of 165 cm. The first side is 65 cm less than twice the second side. The third side is 10 cm less than
Dima020 [189]

Answer:

  • first side: 55 cm
  • second side: 60 cm
  • third side: 50 cm

Step-by-step explanation:

The problem statement gives all the side lengths in terms of that of the second side. Let s represent the length of the second side in cm. Then the length of the first side is (2s-65), and the length of the third side is (s-10). The perimeter is the sum of all the side lengths:

  165 = (2s -65) +s +(s-10)

  165 = 4s-75

  240 = 4s

  60 = s . . . . . . . . second side

  2s-65 = 55 . . . . first side

  s-10 = 50 . . . . . . third side

In order, the side lengths are 55 cm, 60 cm, 50 cm.

4 0
3 years ago
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