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Jlenok [28]
3 years ago
14

A sports store had 60 backpacks in stock, some with wheels and some without wheels, before a new shipment of backpacks arrived.

The number of wheeled backpacks in the new shipment was twice the number of wheeled backpacks already in stock, and the number of backpacks without wheels in the new shipment
was five times the number of backpacks without wheels already in stock. After the new shipment arrived, there
were 330 backpacks in the store. Before the new shipment, there were x wheeled backpacks and y
backpacks without wheels. Which of the following equations can be used with x + y = 60 to solve for x and y?
a. 2x+5y=330
b. 2x+5y=270
c. 5x+2y=270
d. 5x+2y=330
Mathematics
1 answer:
Evgesh-ka [11]3 years ago
4 0
2x + 5y = 270

Two times the amount of wheeled backpacks. Let x = wheeled backpacks.

Five times the amount of non wheeled backpacks. Let y = non wheeled backpacks.

Total backpacks will be 330 so 330 - 60 = 270


Therefore you get 2x + 5y = 270
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3 years ago
Write an equation to represent 'twice a number (x) is fifty"​
V125BC [204]

Hi there,

Your question is "twice a number (x) is fifty"

Recall how a number is represented by x.

Twice a number would be represented as 2x.

Therefore, to represent that twice a number is equal to 50, that would result in the expression: 2x=50

If you're looking to solve this equation, it's often best to think about the "reverse" of the current equation.

Notice how 2 is multiplying the x.

To isolate x, divide that side by 2.

However, recall that whatever is done to one side of an equation must also be done to the other side of the equation. Therefore, you will need to divide both sides by 2.

2x=50

\frac{2x}{2} = \frac{50}{2}

x=25

Equation: 2x=50

Solving for x: 25

Hope that helps!

3 0
3 years ago
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What is the soluition ​
Juli2301 [7.4K]

Answer:

b > 3 2/15.

Step-by-step explanation:

2 3/5  < b - 8/15

b > 2 3/5 + 8/15

b > 13/5 + 8 / 15

b > 39/15 + 8/15

b >  47/15

b > 3 2/15.

5 0
4 years ago
Simplify: (3x – 1) (x3 + 2x + 1)
pshichka [43]

Answer:

B: 3x4-x3+6x2+x-1

5 0
3 years ago
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determine whether the lines intersect and if so find the point of intersection and the cosine of the angle of intersection x=4t+
Fittoniya [83]

Answer:

As the lines are not intersecting nor parallel, they must be skew.

Step-by-step explanation:

Question is incomplete, we consider the nearest match available online.

Parametric equations of two lines are:

L₁ : x=4t+2 , y = 3 , z =-t+1

L₂: x=2s+2 , y= 2s+5 , z = s+1

If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.

4t+2=2s+2 ---(1)\\ \\3=2s+5---(2) \\\\-t+1=s+1---(3)

If lines are intersecting then parametric coordinates must be equal for some value of t and s.

From (3)\\-t=s\\From (2)\\\\s=\frac{3-5}{2}\\\\s=-1\\\implies t=1\\\\To\,\,check\,\, the \,\,values \,\,of \,\,s\,\, and \,\,t \,\,for\,\,intersection\,\,put \,\,them\,\, in\,\, (1)\\\\4(1)+2= 2(-1)+2\\ 6\ne0

Hence the lines are not intersecting nor parallel, they must be skew.

6 0
3 years ago
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