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Jlenok [28]
2 years ago
14

A sports store had 60 backpacks in stock, some with wheels and some without wheels, before a new shipment of backpacks arrived.

The number of wheeled backpacks in the new shipment was twice the number of wheeled backpacks already in stock, and the number of backpacks without wheels in the new shipment
was five times the number of backpacks without wheels already in stock. After the new shipment arrived, there
were 330 backpacks in the store. Before the new shipment, there were x wheeled backpacks and y
backpacks without wheels. Which of the following equations can be used with x + y = 60 to solve for x and y?
a. 2x+5y=330
b. 2x+5y=270
c. 5x+2y=270
d. 5x+2y=330
Mathematics
1 answer:
Evgesh-ka [11]2 years ago
4 0
2x + 5y = 270

Two times the amount of wheeled backpacks. Let x = wheeled backpacks.

Five times the amount of non wheeled backpacks. Let y = non wheeled backpacks.

Total backpacks will be 330 so 330 - 60 = 270


Therefore you get 2x + 5y = 270
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