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mezya [45]
3 years ago
6

A teenage boy is 6 ft tall and casts a shadow of 8ft.What is the distance from the top of his head to the end of his shadow?

Mathematics
2 answers:
Dmitrij [34]3 years ago
7 0
The decimal format of this is 9.16515139

However converted to feet your looking at about 5 feet 2 inches
lisabon 2012 [21]3 years ago
4 0

Answer:

10 feet

Step-by-step explanation:

This image forms a special right triangle: 3-4-5. This represents the ratios of the sides.

Multiplying 3-4-5 by 2, you get 6-8-10. 10 is the hypotenuse (the answer you want) and the only number not listed in the problem.

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Read 2 more answers
2. Which of the following points lies in the solution set of the inequality y>/=3x+10?
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A tent has the dimensions shown in the diagram. Find the area of the groundsheet needed to fit inside the tent. Round your answe
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A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the
EastWind [94]

Answer:

a) \hat p=\frac{471}{1024}=0.460

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Data given and notation  

n=1024 represent the random sample taken    

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

\hat p=\frac{471}{1024}=0.460 estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering    

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

Part b

If we replace the values obtained we got:

0.460-1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.429

0.460+1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.491

The 99% confidence interval would be given by (0.429;0.491)

8 0
3 years ago
Gm everyone how are yall lol
Anni [7]

Answer:

I'm doing good thanks for asking :)

Step-by-step explanation:

I'm also a bit tired and overworked since I have to do online school

7 0
3 years ago
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