Which set of fractions is ordered from least to greatest?

Which fraction is not equivalent to 9/12 a.24/32 b.6/8 c.15/20 d.16/24

stiv31 [10]

The answer is D.

9/12 = 3/4
16/24 = 2/3

2/3 is not equivalent to 3/4

5 0

3 years ago

Here is a triangular pyramid and its net.

galben [10]

Answer:

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. $\text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\$

${\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}$

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

$\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}$

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

$\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}$

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to Lateral Surface Area + Area of base

$\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\ mm^{2}$

Hence,

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

8 0

3 years ago

In Example 3, the track has 6 lanes that are each 1 meter in width. a. What is the outer perimeter of the track? Round your answ

son4ous [18]

Answer:

Incomplete question, check attachment for the necessary diagram

Step-by-step explanation:

Note in the attachment,

We have two identical straight line of lenght

L1 = L2 = 84.39m

We also have two identical semicircle or radius 36.5m to the first track lane

But this is not the radius of the circle, the radius of the circle will now be 36.5 plus the 6 track lane and we are told that one track lane is 1m, then, the track lane is 6m

So, radius = 36.5+6

r = 42.5m

Then, we need to calculate the perimeter of the semicircle using the formula of perimeter of a circle and dividing by2

P = 2πr/2

P =πr

P = 22/7 × 42.5

P = 133.57 m

Then, the arc 1 is equal to arc 2 which is equal to 133.57 m

A1 = A2 = 133.57 m

Now we have all the dimensions,

Then, the perimeter can be calculated by adding the length of the sides

The perimeter of the field = Lenght of the two straight lines plus the length of the two semicircle arc

P = L1 + L2 + A1 + A2

P = 84.39 + 84.39 + 133.57 + 133.57

P =435.923 m

So, to the nearest meter

P ≈ 436m

The perimeter of the track is 436m

5 0

3 years ago

Find the acute angle between the two given lines y=-2x and y=x

Marina CMI [18]

Answer:

θ ≈ 71.6°

Step-by-step explanation:

The angle between two lines with slopes m₁ and m₂ is:

tan θ = | (m₂ − m₁) / (1 + m₁m₂) |

Here, m₁ = -2 and m₂ = 1.

tan θ = | (1 − (-2)) / (1 + (-2)(1)) |

tan θ = | 3 / -1 |

tan θ = 3

θ ≈ 71.6°

3 0

3 years ago

-4(4-4v)-v=-2(-5v-2) answer

nalin [4]

Answer:

Step-by-step explanation:

-16-16v - v = 10v + 4

Add 16 to both sides and combine like terms giving you

15v = 10v + 20

Subtract 10v from both sides

5v= 20

Divide by 5

V=4

3 0

3 years ago

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