Answer:
Int
byte
Explanation:
In java there are eight primitive data types has a class dedicated, and then we can find eight wrapper classes, I'm going to let you the next table with the 8 example:
Assume the next table byte and Int are primitive data, the different with byte is only the capital letter Byte.
Primitive Wrapper Class
boolean Boolean
byte Byte
char Character
int Integer
float Float
double Double
long Long
short Short
In the interview when the candidate is asked about yourself then telling about childhood past is not correct. Therefore the given statement is false.
<h3>What is an interview?</h3>
An interview is an interaction or a conversation between an employer and the interested candidate. In the conversation the interviewee is asked about their education, family background, and work experiences.
When an interviewer ask about tell me about yourself, then the interviewee should not tell about their childhood past, rather the interviewee should give few information about their family, education, and working.
Therefore, the given statement is false.
Learn more about interview, here:
brainly.com/question/13073622
#SPJ1
Advantages of technology in agriculture include expediting crop production rate and crop quantity, which in turn reduces costs of production for farmers and food costs for consumers, and even makes crops more nutritious and livestock bigger and meatier.
The excessive use of chemicals by the help of machines reduces the fertility of the land.Lack of practical knowledge the farmers cant handle the machines properly.While the cost of maintenance is very high.Overuse of machines may lead to environmental damage.It is efficient but has many side effects and drawbacks.
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
</span>
As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
All I will say is good luck. because it can be very difficult to find someone that is willing to do this.
