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My name is Ann [436]
3 years ago
10

. ------------ means that the two merging companiesbecame history and a new firm

Computers and Technology
1 answer:
kirill115 [55]3 years ago
8 0

Answer:

The correct answer is B. Merger means that the two merging companies became history and a new firm is established.

Explanation:

A merger refers to the union of two companies that can be seen as equals. Two companies decide to join forces to increase the strength of their assets, have a greater market and consumer base and ultimately obtain greater profits. The two companies or corporations become joint property and are registered as a new legal entity, which has a different identity from that of the two companies that joined for the merger.

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To differentiate the absolute pathnames to files that are located on different drives, html requires you to include the drive le
Ber [7]
<span>To differentiate the absolute pathnames to files that are located on different drives, HTML requires you to include the drive letter followed by a </span>vertical bar.
4 0
3 years ago
What two statements about IPv6 addresses are true? This task contains the radio buttons and checkboxes for options. The shortcut
Oliga [24]

Answer:

A and C

Explanation:

Option A:

In IPv6 there is a rule to reduce an IPv6 address when there are two or more consecutive segments of zeros just one time. This rule says that you can change the consecutive zeros for “::”  

Here is an example

How to reduce the following IPv6 address?

ff02:0000:0000:0000:0000:0000:0000:d500

Ans: ff02::d500

Example 2:

2001:ed02:0000:0000:cf14:0000:0000:de95

Incorrect Answer -> 2001:ed02::cf14::de95  

Since the rule says that you can apply “::” just one time, you need to do it for a per of zero segments, so the correct answer is:

Correct Answer -> 2001:ed02::cf14:0:0:de95

Or

2001:ed02:0:0:cf14::de95

Option C:

Since in IPv6 there are 2^{128} available addresses which means 340.282.366.920.938.463.463.374.607.431.768.211.456 (too many addresses), there is no need of NAT solution, so each device can have its own IP address by the same interface to have access through the internet if needed. If not, you can block the access through internet by the firewall.

4 0
3 years ago
Fuction table of JK-Flip flop?
vivado [14]

Answer:

Explanation:

The Truth Table for the JK Function. Then the JK flip-flop is basically an SR flip flop with feedback which enables only one of its two input terminals, either SET or RESET to be active at any one time thereby eliminating the invalid condition seen previously in the SR flip flop circuit.

6 0
3 years ago
Write a program that replaces words in a sentence. The input begins with an integer indicating the number of word replacement pa
kramer

Answer: provided in the explanation segment

Explanation:

This is the code to run the program:

CODE:  

//Input: 3 automobile car manufacturer maker children kids

  //15 The automobile manufacturer recommends car seats for children if the automobile doesn't already have one.

  import java.util.Scanner;

  public class LabProgram{

  public static int findWordInWordList(String[] wordList, String wordToFind, int numInList) {

          for (int i = 0; i < numInList; i++) {

              if (wordList[i].equals(wordToFind)) {

                  return i;

              }

          }

          return -1;

      }

      public static void main(String[] args) {

          Scanner scan = new Scanner(System.in);

          String[] original_String = new String[20];

              String[] modified_String = new String[20];

          int numInList = scan.nextInt();

          for (int i = 0; i < numInList; i++) {

              original_String[i] = scan.next();

              modified_String[i] = scan.next();

          }

          int num_Of_Words = scan.nextInt();

          String[] words_To_Replace = new String[num_Of_Words];

          for (int i = 0; i < num_Of_Words; i++) {

              words_To_Replace[i] = scan.next();

          }

          int indx;

          for (int i = 0; i < num_Of_Words; i++) {

              indx = findWordInWordList(original_String, words_To_Replace[i], numInList);

              if (indx != -1)

                  words_To_Replace[i] = modified_String[indx];

          }

          for (int i = 0; i < num_Of_Words; i++)

              System.out.print(words_To_Replace[i] + " ");

          System.out.println();

      scan.close();

      }

  }

cheers i hope this helps!!!!1

3 0
4 years ago
Using MARS/MIPS
slega [8]

Answer:

Explanation:

MIPS program which increments from 0 to 15 and display results in Decimal on the console

In this program the user defined procedures print_int and print_eot were used to print the integer values and new line characters(\n) respectively.the mechanisam of the loop is explaine in the comment section of the program.

     addi $s0, $0, 0

     addi $s1, $0, 15

print_int:

              li $v0, 1                # system call to print integer

              syscall                

              jr $ra                     # return

print_eol:                      # prints "\n"

            li $v0, 4            

              la $a0, linebrk      

              syscall              

              jr $ra                  # return

main: . . .          

              li $a0, 0                # print 0

              jal print_int         # print value in $a0

loop:   move $a0, $s0           # print loop count

       jal print_int        

       jal print_eol           # print "\n" character

       addi $s0, $s0, 1        # increment loop count by 1

       ble $s1, $s0, loop      # exit if $s1<$s0

beq $s0, $0, end

end:

MIPS progam to increment from 0 to 15 and display results in Hexadecimal on the console

this program is slightly differed from the previous program in this program the system call issued in print_int is implemented with a system call that prints numbers in hex.

addi $s0, $0, 15

     addi $s1, $0, 0

print_int:

   li      $v0,34                  # syscall number for "print hex"

   syscall                         # issue the syscall

              jr $ra                     # return

print_eol:                      # prints "\n"

            li $v0, 4            

              la $a0, linebrk      

              syscall              

              jr $ra                  # return

main: . . .          

              li $a0, 0                # print 0

              jal print_int         # print value in $a0

loop:   move $a0, $s0           # print loop count

       jal print_int        

       jal print_eol           # print "\n" character

       addi $s0, $s0, 1        # increment loop count by 1

       ble $s1, $s0, loop      # exit if $s0>$s1

beq $s0, $0, end

end:

5 0
3 years ago
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