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Lana71 [14]
3 years ago
10

a teacher is experimenting with computer- based instruction. In which situation could the teacher use a hypothesis test for a di

fference in two population means
Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0

Answer:

(i) She gives each student a pretest. Then she teaches a lesson using a computer program. Afterwards, she gives each student a posttest. The teacher wants to see if the difference in scores will show an improvement.

Step-by- Step

The situation is a case of matched or paired samples since the samples are dependent. The two measurements are drawn from the same pair of individuals The parameter that is tested using matched pairs is the population mean and this is what teacher intends to use a hypothesis test for.

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7x - 8 = 41 what does x equal to
velikii [3]

Answer:

7

Step-by-step explanation:

41+8=49 49/7=7

4 0
2 years ago
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If the length of a rectangular television screen is 20 inches and its height is 15 inches,
scoundrel [369]
Use the Pythagorean theorem: 

<span>C = √[a^2 + b^2] </span>
<span>C = √[(20^2 + 15^2] </span>
<span>C =√[400 + 225] </span>
<span>C = √(625) </span>
<span>C = 25 inches </span>

Answer: 3.25 inches <span>✔️</span>
4 0
3 years ago
How do u determine the equation of the line through each pair of points in slope-intercept form (y=mx+b). (3,0) and (2,4) (-6,3)
steposvetlana [31]

Answer:

Y =-4X +12

Y =-0.625X  -0.75

Step-by-step explanation:

(3,0) and (2,4)....

x1 y1  x2 y2

3 0  2 4

   

(Y2-Y1) (4)-(0)=   4  ΔY 4

(X2-X1) (2)-(3)=    -1  ΔX -1

   

slope= -4          

B= 12          

   

Y =-4X +12    

~~~~~~~~~~~~~~~~~

(-6,3) and (2,-2)​

x1 y1  x2 y2

-6 3  2 -2

   

(Y2-Y1) (-2)-(3)=   -5  ΔY -5

(X2-X1) (2)-(-6)=    8  ΔX 8

   

slope= -  5/8    

B= -  3/4    

   

Y =-0.625X  -0.75    

6 0
3 years ago
Helpp!!
IRISSAK [1]

Answer:

15 seventh graders

Step-by-step explanation:

1/5 of 75 is 15

6 0
3 years ago
Read 2 more answers
Step 3a: Calculating the average rate
Alex73 [517]

9514 1404 393

Answer:

  a) average rate = (total distance)/(total time)

  b) Rave = 2·R1·R2/(R1 +R2)

  c) cheetah's average rate ≈ 50.91 mph

Step-by-step explanation:

a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...

  First leg distance: AB = 70·t1   ⇒   t1 = AB/70

  Second leg distance: AB = 40·t2   ⇒   t2 = AB/40

The average rate is the ratio of total distance to total time:

  average rate = (AB +AB)/(t1 +t2)

  average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)

  average rate = 560/11 = 50 10/11 . . . mph

__

No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.

b) For two rates over the same distance (as above), the average is their harmonic mean:

  average rate = 2r1·r2/(r1+r2)

__

c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.

4 0
3 years ago
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