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3 years ago

12

HELP ME PLEASE

1 answer:

Darina [25.2K]3 years ago

7 0

X equals 90 because 360 /2=

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35,000 divided by 120

Naya [18.7K]

Answer:

291.666666667

Step-by-step explanation:

Rounds to 291.7

8 0

2 years ago

Read 2 more answers

What is the slope of the line that passes through the points (6, -5) and (6, -8)?

Anni [7]

(6,-5) (6,-8)

y2-y1/x2-x1

-8+5/6-6

-3/0

Undefined should be the answer. Hope this helped (:

4 0

3 years ago

What is the slope of a line perpendicular to line 6x + 3y = 15

NISA [10]

Step-by-step explanation:

Given line is 6x+3y=15

Slope of the given line (m)=-x/y

=-6/3

=-2

let slope of the line perpendicular to the given line be m'.

Condition of perpendicularity,

m×m'=-1

-2×m'=-1

m'=-1/-2

m'=1/2

8 0

2 years ago

I don't understand.

Hoochie [10]

Answer:

Addition property of equality.

Step-by-step explanation:

You are adding something to both sides of the equation.

8 0

2 years ago

Read 2 more answers

For each of the following vector fields

olga nikolaevna [1]

(A)

$\dfrac{\partial f}{\partial x}=-16x+2y$

$\implies f(x,y)=-8x^2+2xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=10y$

$\implies g(y)=5y^2+C$

$\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}$

(B)

$\dfrac{\partial f}{\partial x}=-8y$

$\implies f(x,y)=-8xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x$

$\implies \dfrac{\mathrm dg}{\mathrm dy}=x$

But we assume $g(y)$ is a function of $y$ alone, so there is not potential function here.

(C)

$\dfrac{\partial f}{\partial x}=-8\sin y$

$\implies f(x,y)=-8x\sin y+g(x,y)$

$\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=4y$

$\implies g(y)=2y^2+C$

$\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}$

For (A) and (C), we have $f(0,0)=0$ , which makes $C=0$ for both.

4 0

3 years ago