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erastovalidia [21]
3 years ago
15

Solve: /3=46 x/3 is a fractions

Mathematics
1 answer:
den301095 [7]3 years ago
8 0

answer :138

x/3=46

x=46*3

x=138

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14. Find the Error Hiroshi is determining -42 – (-37). Find his
vaieri [72.5K]

Answer:

Hiroshi's error was not having changed the sign of the number 37 by removing the parentheses and placing -37 instead of +37.

Step-by-step explanation:

we have

Hiroshi's work

42-(-37)=42-37=5

Remember that

a negative number is just a positive number multiplied by -1

and (-1)(-1)=+1

so

Correct work

42-(-37)

42-(-1)(37)

42-(1)(-1)(37)

42+(-1)(-1)(37)

=42+37=79

therefore

Hiroshi's error was not having changed the sign of the number 37 by removing the parentheses and placing -37 instead of +37.

3 0
3 years ago
Please do 3 & 4 and show work
Shalnov [3]

Answer:

3. A=B=70°; C=D=110°

4. A=90°; C=48°

Step-by-step explanation:

Same-side angles of a trapezoid add to 180°.

___

3. (2x) +(x+15) = 180

3x + 15 = 180 . . . . simplify

x +5 = 60 . . . . . . . divide by 3

x = 55

A=B=(x+15)° = (55+15)° = 70°

C=D=2x° = 2·55° = 110°

__

4. You are given the values of one of the angles on each side, so the other can be found by subtraction:

A=180°-D = 90°

C = 180° -132° = 48°

8 0
3 years ago
RSM wants to send four of its 18 Math Challenge teachers to a conference. How many combinations of four teachers include exactly
tatiyna

Answer:

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

Step-by-step explanation:

The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

1 from a set of 2(Either Mrs. Vera or Mr. Jan).

3 from a set of 18 - 2 = 16. So

C_{2,1}C_{16,3} = \frac{2!}{1!1!} \times \frac{16!}{3!13!} = 1120

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

4 0
3 years ago
How many 4 digit multiples can not be divided by 5
Advocard [28]

Answer:

1800

Step-by-step explanation:

Let us solve this question by Modular Airthmatic.

Let the lowest 4 digit number be X.

X= 1 (mod 5)

X =2 (mod 5)

X=3 (mod 5)

X =4 (mod 5)

X=1+5 t where t is any integer.

1+5 t=2 (mod 5)

5 t=1 (mod 5 )

5 is the Modular Inverse of modulo 5

t=1 (mod 5)

t =1+5 u : u= any integer.

X becomes 1+ 5 (1+5u )=6+25 u

6+25u =3 (mod 5)

25 u= -3 (mod 5)=2 (mod 5)

25 is Modular Inverse of Modulo 5

u=2 (mod 5)

u =2+5 v : v= any integer.

X becomes 6 +25 (2+5 v)=56+125 v .

56 +125 v=4 (mod 5)

125 v=-52 (mod 5)=3 (mod 5)

125 is Modular Inverse of modulo 5

v = 3 (mod 5)

v =3 +5 w where w is any integer.

For lowest 4 digit number, take

w=200

X=1003 : Lowest 4 digit number.

Take w=201

X=208 : Next number.

For 4 digit largest number, take

w=1995

X= 9978 : Largest number.

No. of Numbers =(1995 - 200 )+1=1800 □Ans.

8 0
3 years ago
Read 2 more answers
Question in the picture<3
SVEN [57.7K]
It whould be 8 because if you divide it
5 0
3 years ago
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