Equation parallel to y = -x is y=-x+k
so 4.5 = -7 + k so k - 11.5
Equation is y = -x + 11.5
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
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Answer:
- 30m +50 = 20m +100
- m = 5
- yes. symmetric property of equality.
Step-by-step explanation:
1. The expression for c in the first equation is (30m+50). Substituting that for c in the equation ...
c = 20m +100
gives you ...
30m +50 = 20m +100
__
2. Adding -50-20m to both sides gives ...
10m = 50
m = 5 . . . . . . . divide by 10
__
3. Doing the substitution in reverse, you would substitute (20m+100) for c in the equation ...
c = 30m +50
to get ...
20m +100 = 30m +50
This is the equation of part 1 with the expressions swapped to the other side of the equal sign. The symmetric property of equality tells you that changing sides of the equal sign does not change the value of the variable(s).
You get the same solution.
