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3 years ago

Distance from -3 to 0

Mathematics

1 answer:

pickupchik [31]3 years ago

7 0

The space from -3 to 0 is 3 units. The answer is positive 3, not negative.

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1/x-2 graphed<br><br><img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx-2%7D" id="TexFormula1" title="\frac{1}{x-2}" alt="\fra

bearhunter [10]

Answer:

Step-by-step explanation:

The given equation is expressed as

y = 1/(x - 2)

We will assume values for x and determine the corresponding values for y. Therefore,

When x = 0, y = 1/(0 - 2) = - 1/2

When x = 1, y = 1/(1 - 2) = - 1

When x = 2, y = 1/(2 - 2) = 0

When x = 3, y = 1/(3 - 2) = 1

When x = 4, y = 1/(4 - 2) = 1/2

To plot the graph, we would choose a suitable scale for the x and y axis of the graph.

Let 2 cm represent 1 unit on the vertical axis.

Let 2 cm represent 0.5 unit on the x axis.

The graph is shown in the attached photo

4 0

3 years ago

Jaylan decided she no longer liked the car she was leasing and turned it in 1

Stolb23 [73]

Answer:

Step-by-step explanation:

I'm pretty sure its lease penalty

5 0

3 years ago

Question 5 (1 point) Most fossils are two million years old. True False

Vikki [24]

Answer:

False

Step-by:-step explanation

2 million years

The oldest reliably classified fossils belonging to the genus Homo date back to a little over 2 million years ago. They belong to H. habilis, a type of ancient hominin that scientists classify as the first of our genus, and which may have led to H. erectus, one of our direct ancestors

6 0

3 years ago

Read 2 more answers

LM is the midsegment of trapezoid ABCD. AB= x + 8, LM = 4x + 3, and DC = 187. What is the value of x?

beks73 [17]

$\frac{|DC|+|AB|}{2}=|LM|\\\\|AB|=x+8;\ |LM|=4x+3;\ |DC|=187\\\\substitute:\\\\\frac{187+x+8}{2}=4x+3\ \ \ \ /\cdot2\\\\195+x=8x+6\ \ \ /-195;\ /-8x\\\\-7x=-189\ \ \ /:7\\\\\underline{\underline{x=27}}$

5 0

3 years ago

A study of pollutants showed that certain industrial emissions should not exceed 2.3 parts per million. You believe a particular

Musya8 [376]

Answer:

$t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5$

The degrees of freedom are given by:

$df=n-1=9-1=8$

And the p value would be:

$p_v =P(t_{(8)}>7.5)=0.0000346$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 2.3 ppm the safe limit

Step-by-step explanation:

Information provided

$\bar X=3.3$ represent the sample mean in ppm

$s=0.4$ represent the sample standard deviation

$n=9$ sample size

$\mu_o =2.3$ represent the value to verify

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true mean is higher than 2,3 ppm, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2.3$

Alternative hypothesis: $\mu > 2.3$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5$

The degrees of freedom are given by:

$df=n-1=9-1=8$

And the p value would be:

$p_v =P(t_{(8)}>7.5)=0.0000346$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 2.3 ppm the safe limit

6 0

4 years ago

Distance from -3 to 0​

Distance from -3 to 0