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RSB [31]
2 years ago
15

In a bag of marbles, 1/2 are red, 1/4 are blue, 1/6 are green and 1/12 are yellow. You pick a marble without looking. What color

marble are MOST likely to be choose?
Mathematics
1 answer:
igomit [66]2 years ago
6 0

Answer:

Its red becasue 1/2 is greater than all of them

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svetlana [45]

Answer:

A) plot a point on 9.8 on age 9 and 11 on age 7

B) Negative

C) line of best fit is just going through the middle

7 0
2 years ago
Read 2 more answers
PLEASE HELP ASAP
IrinaK [193]

Answer:

{x,y} = {3,2}

Hope this helps!

Step-by-step explanation:

Brainliest?

5 0
3 years ago
Stefan spent half of his weekly allowance on clothes. To earn more money his parents let him wash the car for $5
Alenkasestr [34]
8-5=3 is the remaining half
weekly allowance=2(1÷2) where (1÷2) is 3
2×3=6

The weekly allowance should be 6.
7 0
3 years ago
Jack and Jill live 126 km apart. They want to leave their homes at the same time,
Digiron [165]

Answer:

Both will leave their homes to meet on time at 9 am  

Step-by-step explanation:

Given as, Distance between Jack  and Jill = 126 km

Speed of Jack rides = 18 kilometers per hours

Speed of Jill rides     = 24 kilometers per hours

Let the distance travel by Jack = x km

And the distance travel by Jill  =  (126 - x ) km

Time taken by Jack and Jill = T hours

Now , Distance = Speed × Time

So,     x = 18 × T

And  126 - x = 24 × T

Or,    126 - x =  24 × \frac{x}{18}

Or,    126 - x =  x × \frac{4}{3}

Or,    378 - 3x = 4x

Or,    378 = 7x

i.e x = \frac{378}{7} = 54 km

And distance travel by Jill = 126 - 54 = 72 km

So, time taken by Jack = \frac{x}{18} = \frac{54}{18}

Or, Time taken by Jack = 3 hours

Similarly Time take by Jill = \frac{72}{24} = 3 hours

∵ Both Jack and Jill will take 3 hours to meet at 12 : 00 pm

Hence, Both will leave their homes to meet on time at 9 am   Answer

7 0
3 years ago
I have an hour to finish, help a girl out
mr_godi [17]

If you're going to use technology (Brainly) to solve this problem, you might find you get a quicker answer using the technology of your graphing calculator.

It is often convenient to cast the problem in the form f(θ) = 0. You can do that by adding 1 to both sides of the equation.

4\sqrt{2}\cos{(\theta)}+4=0\\ \cos{(\theta)}+\dfrac{1}{\sqrt{2}}=0\qquad\mbox{divide by $4\sqrt{2}$}\\ \cos{(\theta)}=\dfrac{-\sqrt{2}}{2}\qquad\mbox{subtract $\dfrac{1}{\sqrt{2}}$}\\\\ \theta=\{\dfrac{3\pi}{4},\dfrac{5\pi}{4}\}\qquad\mbox{determine the corresponding angles}

3 0
3 years ago
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