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marin [14]
2 years ago
13

Select the correct answer. A and АВ: Which matrix is matrix B?

Mathematics
1 answer:
Kruka [31]2 years ago
5 0

Answer:

Option B

Step-by-step explanation:

Looking at the options, option B is correct because when multiplying it by matrix A, it yields the matrix AB as follows;

First row of A multiplied by first column of matrix in option D;

(1 × -1) + (0 × 0) + (0 × 0) = -1 which corresponds to the first number on the first row of Matrix AB

Since majority of matrix AB are zero, I will just prove the ones that are not zero.

Thus;

Second row of matrix A is multiplied by second column of matrix in option D;

(0 × 0) + (-1 × -1) + (0 × 0) = 1 which is same as 2nd number on second row in matrix AB

Lastly, third row of matrix A is multiplied by third column of matrix in option D;

(0 × 0) + (0 × 0) + (1 × -1) = -1 which is same as third number in third row in matrix AB

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\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k

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\vec\imath\times\vec\jmath=\vec k

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\vec k\times\vec\imath=\vec\jmath

and that for any two vectors \vec a and \vec b, \vec a\times\vec b=-\vec b\times\vec a, and \vec a\times\vec a=\vec0.

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\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k

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with respect to y and

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