Assume P(xp,yp), A(xa,ya), etc.
We know that rotation rule of 90<span>° clockwise about the origin is
R_-90(x,y) -> (y,-x)
For example, rotating A about the origin 90</span><span>° clockwise is
(xa,ya) -> (ya, -xa)
or for a point at H(5,2), after rotation, H'(2,-5), etc.
To rotate about P, we need to translate the point to the origin, rotate, then translate back. The rule for translation is
T_(dx,dy) (x,y) -> (x+dx, y+dy)
So with the translation set at the coordinates of P, and combining the rotation with the translations, the complete rule is:
T_(xp,yp) R_(-90) T_(-xp,-yp) (x,y)
-> </span>T_(xp,yp) R_(-90) (x-xp, y-yp)
-> T_(xp,yp) (y-yp, -(x-xp))
-> (y-yp+xp, -x+xp+yp)
Example: rotate point A(7,3) about point P(4,2)
=> x=7, y=3, xp=4, yp=2
=> A'(3-2+4, -7+4+2) => A'(5,-1)
Get the y alone.
-3+y=11
+3 on both sides
y=14 = y intercept
-x+y=2
Add x to both sides of the equation
Y= 2 + x
A function associates x and y values. The graph of the function is formed by all the points 
such that x and y are actually associated, i.e. y=f(x).
So, if you choose x=4, you can see that the correspondant point on the graph has a y coordinate that is somewhere between 3 and 4 - much closer to 4 actually.
So, an estimated value could be around 3.75
Answer:
(3.5, - 3.5)
Step-by-step explanation:
Using the Midpoint theorem, we have
x=(9-2)/2=7/2=3.5
y=(-8+1)/2=-7/2=-3.5
