What would the coordinates be if Figure A was dilated to three times the size and reflected across the y-axis?

Suppose f(x) is a function such that for some positive integer n, f has n linearly dependent derivatives. In other words, if f(x

Anon25 [30]

Answer:

See explaination for the prove of the statement.

Step-by-step explanation:

To establish this prove, lets refer back to what we already know.

We know that "If the set of reactions {d1,d2,d3,......dn} in a vector space V over a field f be linearly dependent, then atleast one of the vectors of the set can be expressed as a linear combination of the remaining others.

Please kindly go to attachment for a detailed step by step explaination of the prove.

6 0

3 years ago

How much of the backyard is NOT being used for a vegetable garden or pet exercise area?

Nimfa-mama [501]

Area of backyard is not being used 7792 square feet.

Solution:

Length of the backyard = 181 ft

Width of the backyard = 48 ft

Area of the backyard = length × width

= 181 × 48

Area of the backyard = 8688 square feet

Base of the triangle = 16 ft

Height of the triangle = 28 ft

Area of the triangle = $\frac{1}{2}\times \text{base}\times \text{height}$

$$=\frac{1}{2}\times {16}\times {28}$

Area of the triangle = 224 square feet

Length of the rectangle = 32 ft

Width of the rectangle = 21 ft

Area of the rectangular vegetable garden = length × width

= 32 × 21

Area of the rectangular vegetable garden = 672 square feet

Area of backyard not used

= Area of backyard – Area of the triangle + Area of the rectangle

= 8688 – 224 – 672

= 7792 square feet

Area of backyard is not being used 7792 square feet.

3 0

4 years ago

What does that equation equal??

sattari [20]

Answer:

y = 5.543

Step-by-step explanation:

Your y = 7(1 - 0.021)^11 is evaluated as follows:

y = 7(0.979)^11

y = 7(0.7918

y = 5.543

3 0

4 years ago

If the set U = {all positive integers} and set A = {x|x ∈ U and x is an odd positive integer}, which describes the complement of

dlinn [17]

Answer: Choice D) set of even integers

=======================================================

Explanation:

U = universal set = {all positive integers} = {1, 2, 3, 4, 5, ...}

A = {stuff in set U that is odd} = {1, 3, 5, 7, 9, ...}

$A^c$ = {stuff in set U but NOT from set A} = {2, 4, 6, 8, ...}

$A^c$ = {set of even numbers from set U}

In set theory, the complement is simply the complete opposite. If the number 7 is found in set A for instance, then 7 is not going to live in the complement $A^c$

The opposite of the odd numbers is the set of even numbers.

Therefore, we go for <u>choice D</u> as our final answer.

Side note: if we union set A with its complement $A^c$ then we get the universal set as a result. $A \cup A^c = \text{universal set} = \text{set of all positive integers}$