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garri49 [273]
3 years ago
6

Which statement is NOT true about the figure below?

Mathematics
1 answer:
lidiya [134]3 years ago
8 0

Answer:

Step-by-step explanation:

the answer is C

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Find the point-slope form of the equation of the line that passes through (4, -2) With a slope of 1/4
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(y+2)=1/4(x-4) is the answer because you use the formula (y-y1)=slope(x-x1)
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The following are the temperatures of 10 days in winter in °C. − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3 Work out the mean
marissa [1.9K]

The mean temperature of the given data − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3 is 1.9

mean= 1.9

<h3>What is mean of the data?</h3>

The mean, or average, is calculated by adding up the data and dividing by total number of data.

Given data: − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3

Now, mean =   \frac{sum \;of\; observation}{Total \;number \;of \;observation}

mean = \frac{(-3)+ 0+10+2+8+(-5)+ (-1)+ 9+2+(-3)}{10}

           = \frac{19}{10}

mean= 1.9

Hence, the mean of − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3  is 1.9

Learn more about mean here:

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3 0
2 years ago
In slope intercept form what is the equation of the line having a slope of 5 and passing through the point (-6,-26)
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Slope/gradient = 5
y= MX + C
(-6,-26)
-6 is x1 and -26 is y1
so therefore y= 5x -26
5 0
3 years ago
The parametric equations x = x1 + (x2 − x1)t, y = y1 + (y2 − y1)t where 0 ≤ t ≤ 1 describe the line segment that joins the point
Ulleksa [173]

It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.


For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).

... x = 1 + t(3-1)

... y = 1 + t(4-1)

ab = {x=1+2t, y=1+3t}


For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).

... x = 3 + t(1-3)

... y = 4 + t(7-4)

bc = {x=3-2t, y=4+3t}


For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).

... x = 1 + t(1-1)

... y = 7 + t(1-7)

ca = {x=1, y=7-6t}

4 0
3 years ago
Divide 1-k^3 by k-1​
UNO [17]

Answer:

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Step By Step:

Cancel the common factor.

Then.

k 2 + k +1 by 1

Gets you k2+k+1

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