C.the height of a student and the the day of a month a student was born
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Answer:
Step-by-step explanation:
4/x + 4/(x²-9) = 3/(x - 3)
4 / x + 4 / [( x - 3) ( x + 3 )] = 3 / ( x - 3 ) / * x ( x - 3 ) ( x + 3 )
Restrictions : x ≠ 0, x ≠ - 3 , x ≠ 3;
4 ( x + 3 ) ( x - 3 ) + 4 x = 3 x ( x + 3 )
4 ( x² - 9 ) + 4 x = 3 x² + 9 x
4 x² - 36 + 4 x - 3 x² - 9 x = 0
x² - 5 x - 36 = 0
x² - 9 x + 4 x - 36 = 0
x ( x - 9 ) + 4 ( x - 9 ) = 0
( x - 9 ) ( x + 4 ) = 0
x - 9 = 0, or : x + 4 = 0
Answer:
x = 9, x = - 4
Which value in this data set is an outlier? 4, 5, 1, 7, 4, 5, 8, 9, 6, 5, 4, 9, 7
omeli [17]
1 is your answer
Note that all the other numbers are inbetween 4 and 9. 1 however, is outside the amount, therefore, your outlier is 1
hope this helps
