The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x
Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y
10y+ x-36=10x+y
Substitute y with 14-x
So we would get
10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5
Y=14-x
=14-5
=9
So the two digit number is
10y+x
=90+5
=95
Answer:
-25
Step-by-step explanation:
g(f(3))= g(-5)
=4(-5)-5
= -20-5
=-25
Given the functions
(a) f(x) = x³ + 5x² + x
(b) f(x) = x² + x
(c) f(x) = -x
Function (a)
f(-x) = (-x)³ + 5(-x)² + (-x)
= -x³ + 5x² - x
= -(x³ - 5x² + x)
The function is neither even nor odd.
Function (b)
f(-x) = (-x)² + (-x)
= -(-x² + x)
The function is neither even nor odd.
Function (c)
f(-x) = -(-x)
= x
= -f(x)
Because f(-x) = -f(x) the function is odd.
Answer: f(x) = -x is an odd function.
Answer:
140
Step-by-step explanation:
46+94 = 140
Answer:
Step-by-step explanation:
5x-2y=24
x+2y=12
add the two equations
(5x-2y)+(x+2y)=24+12
6x=36
x=6
Plug in x=6 into any of the two equations
5(6)-2y=24
30-2y=24
-6= -2y
y= 3
x=6
y=3
(6,3)
