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3 years ago

You are going to roll two dice. Let the variable x = the sum of the numbers rolled. What is the probability that x = 9 ?

1 answer:

7 0

The first cube can land in any one of 6 ways.
The second cube can land in any one of 6 ways.
Total number of ways that 2 dice can land = (6 x 6) = 36 ways.

For any of these ways, the sum of the numbers rolled is 9 :

3, 6
4, 5
5, 4
6, 3

There are 4 ways to roll a 9, out of a total of 36 ways that
the dice can land. So the probability of rolling a 9 is

4 / 36 = 1 / 9 = <em>11-1/9 percent</em>

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1+2=21, 2+3=36,3+4=43,4+5=?

Anni [7]

1+2=21, 2+3=36, 3+4=43, 4+5=52.

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3 years ago

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Can somebody answer this for me, please? <br><br> **_You get 20 Points_**

nevsk [136]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Use this formula:

Area = ((a + b)/2) x h

a is the top length

b is the bottom length

h is the vertical height

1) Substitute in the values:

((3.8 + 6.2)/2) x 7 = 35ft^2 <== this is the answer

2) Substitute in the values:

((10.3 + 15.1)/2) x 12.6 = 160.02in^2 <== this is the answer

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

3 0

3 years ago

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Change 6.00pm to 24 hours clock time<br><br>use a colon <br><br>

kkurt [141]

Answer:

Step-by-step explanation:

6:00 PM equals 18:00 in 24 hrs clock time.

<h3>Hope it helps you.. </h3>

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3 years ago

My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the

AVprozaik [17]

Answer:

a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

b) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=\pm 1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.02$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use $\hat p =0.5$

$n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

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3 years ago

WILL GIVE 30 points a scatter plot and a possible line of best fit is shown is the line of best fit accurate for the data shown

mart [117]

It passes through the center of the points. (2)
When doing a line of best fit, you want the line to have equal number of points on either side of the line.

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4 years ago

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